> 2. I do not believe it is possible to state how the 4th dynasty
> Egyptians would have achieved it because there are no written
> records from the 4th dynasty speculation is o.k., actually
> speculation is all that we have.
That is what I used in the first post.
The AE method of area was subtract 1/9 and make the diameter the side length of a square and find area.
I just added 1/9th to diameter and set it as the diagonal and multiply by the sqrt of 2 inherent in the diagonal then doubled it since two halfs of square.
The two main lines in a square are the side and diagonal.
They subtracted 1/9th so I decided to add 1/9th.
Circumference is what it got me.
Ex. diameter of 9(papyrus ex.).
9 - 1/9 = 8
8 * 8 = 64 area
Actual = 63.617.......
9 + 1/9 = 10
10 * sqrt2 * 2= 28.28427...
Actual = 28.27433...
So diameter as side = area
diameter as diagonal = circumference.
Not claiming they used it but jsut that I used what they used and expanded to the next logical thing to attempt for both the square and circle in the relationship the AE created in their maths.
|No pi challenge||140||Sirfiroth||07-Feb-11 02:09|
|Re: No pi challenge||76||Ahatmose||07-Feb-11 02:27|
|Re: No pi challenge||51||Sirfiroth||07-Feb-11 02:51|
|Re: No pi challenge||87||lobo-hotei||07-Feb-11 04:29|
|Re: No pi challenge||88||Sirfiroth||07-Feb-11 15:56|
|Re: No pi challenge||92||Spiros||07-Feb-11 14:48|
|Re: No pi challenge||84||Sirfiroth||07-Feb-11 18:18|
|Re: No pi challenge||101||lobo-hotei||07-Feb-11 18:30|
|Re: No pi challenge||92||MJT||07-Feb-11 20:11|
|Re: No pi challenge||86||MJT||07-Feb-11 16:07|
|Re: No pi challenge||87||Sirfiroth||07-Feb-11 18:31|
|Re: No pi challenge||103||lobo-hotei||08-Feb-11 14:44|
|Re: No pi challenge||69||Sirfiroth||09-Feb-11 00:52|