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Well going for the square to circle conversion:
C/4 /sqrt2 / 10 * 9 = R
C= Circumference
4= sides of square
sqrt2= ratio of diagonal to square(this is the diameter as diagonal vs. side length in the Papyrus)
10/9= conversion of diameter as diagonal length to side length.
In the papyrus they subtracted 1/9 for side length. I added 1/9 for the diagonal.
You could also divide by 8 multiply by sqrt2 and then divide by 10/9 about the same in a roundabout way.
Regards,
Lobo-hotei
lobo
C/4 /sqrt2 / 10 * 9 = R
C= Circumference
4= sides of square
sqrt2= ratio of diagonal to square(this is the diameter as diagonal vs. side length in the Papyrus)
10/9= conversion of diameter as diagonal length to side length.
In the papyrus they subtracted 1/9 for side length. I added 1/9 for the diagonal.
You could also divide by 8 multiply by sqrt2 and then divide by 10/9 about the same in a roundabout way.
Regards,
Lobo-hotei
lobo
Subject | Views | Written By | Posted |
---|---|---|---|
No pi challenge | 140 | Sirfiroth | 07-Feb-11 02:09 |
Re: No pi challenge | 76 | Ahatmose | 07-Feb-11 02:27 |
Re: No pi challenge | 51 | Sirfiroth | 07-Feb-11 02:51 |
Re: No pi challenge | 86 | lobo-hotei | 07-Feb-11 04:29 |
Re: No pi challenge | 88 | Sirfiroth | 07-Feb-11 15:56 |
Re: No pi challenge | 92 | Spiros | 07-Feb-11 14:48 |
Re: No pi challenge | 84 | Sirfiroth | 07-Feb-11 18:18 |
Re: No pi challenge | 101 | lobo-hotei | 07-Feb-11 18:30 |
Re: No pi challenge | 92 | MJT | 07-Feb-11 20:11 |
Re: No pi challenge | 86 | MJT | 07-Feb-11 16:07 |
Re: No pi challenge | 87 | Sirfiroth | 07-Feb-11 18:31 |
Re: No pi challenge | 103 | lobo-hotei | 08-Feb-11 14:44 |
Re: No pi challenge | 69 | Sirfiroth | 09-Feb-11 00:52 |
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