Spiros Wrote:
-------------------------------------------------------
> Hello engbren,
>
> An interesting match. But we need to keep in mind
> that the orbit is highly eccentric and I don't
> know what the degree of error is.

Yes - I could only find the statement of about 8.5 AU nothing which notes the likely error in that.

Also, There
> haven't been any planets discovered in this star
> system. Alhena's crossing the Meridian is close to
> that of Orion, but I don't know how it, as a star
> has relevance to the specific dates encoded in the
> Westcar papyrus. If dates are encoded, they should
> mark a significant event, like let's say the birth
> or death of a Pharaoh or his becoming King. If I
> remember correctly, you pointed out a date where
> the Moon aligns with Gemini. I think my
> calculations are correct because they tie into the
> exact time that Saturn is at a specific distance
> from the Earth. Saturn is also one of the stars
> that form the 3 Giza pyramid shape(triangle). The
> Moon is in fact in an interesting position and it
> is visually close to Saturn. I don't thus see an
> exact correlation with Alhena. Nonetheless, we can
> consider the succession of constellations of the
> Zodiac, Cancer, Gemini, Taurus, Aries, etc. There
> are no bright stars in Cancer. At the time of
> Aldebaran's transit, Saturn is below the horizon.
> As pointed out before, Aldebaran's and Capella's
> upper culmination align with Thuban's lower
> culmination thus probably forming what the AE
> called the Mooring Post.
>
>
>
> pic from:
>
> [members.westnet.com.au]
>
> The vertical pole.
>
> But if we look at Gemini's upper culmination, then
> we notice that Saturn as also the Moon have
> risen.
>
> BR Spiros

I’ve dropped a note here that explains some of the significance of Alhena:

[grahamhancock.com]

Aside from being 109+-8 light years away which setting at 110 light years Which is an integer divisible of the baselength of 440 Royal Cubits.

Alhena also has a mass of 2.8 times that of our sun providing a possible link to the height of 280 Royal Cubits. I don’t know the error in that calculation either.