I am not sure what this is in nautical miles because I don't work in them.
'1° arc = 364953 3/5 feet, 1 nautical mile = 6082 14/25 feet, with 1/8 being equal to the South Side Base G1 760 8/25 feet. '
Using the canon of ancient measure this can be converted into imperial miles very simply.
364953.6 x 360 = 131383296 / 5280 = EXACTLY 24883.20 imperial miles. The geodetic basis of all ancient measures.
Using the canon 364.9536 represents solar days because solar days x 1000 x 360 / 5280 is the formula.
If 364.9536 days is represented by 13183296 imperial feet then 366.666r days is represented by 132000000. This is a base 1000 unit of measurement when the barleycorn foot is 0.3666r imperial feet.
I just don't see how the south side base of G1 is anywhere near 760 8/25 using Petrie's analysis. It is 755.75 nearly five foot different.
just Googled the length of the nautical mile and yes there are 21600 nautical miles in the meridian circumference. Knock me over with a feather.
It is also 6300 Spanish leagues and 21600 / 6300 = 22/7 x 1.08 x 100/99. Blow me.
If there are 21600 nautical miles in 24883.20 miles the one in feet is 6082.56 imperial feet.
This is 1.152 normal miles.
11.52 / 12 = 0.96 as a matter of interest.
1.152 x 12 = 13.824
0.624 more that 13.2
13.2 / 0.624 x 7 = 27.5 as a matter of interest.
according to Knight and Butler the layout of the Giza plateau and Thornborough are in the same ratios and they go on to produce a 2.72 foot calculation at Thornborough for the megalithic yard of 2,72 imperial feet.
If Hugh Franklin's megalithic yard of 2.7207 is used at Giza then
1111.111r megalithic yards give 36276 inches 3023 imperial feet or one side of Petrie's 755.75 feet.
Edited 9 time(s). Last edit at 03-Dec-18 20:24 by DavidK.