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Stephen

thanks, your SOL calculations led me to look for n/(n-1) links between our findings an Manu supplied the background as the links between the cubit the metre and the foot totalling 72 with the foot constant at 12 the metre plus the cubit are two variables totalling 60.

So the ancient metre you use as 39.375 gives a variable cubit of 20.625 imperial inches x 17.60 or 17600/100 gives 363 solar days at the GP.

The length of the foot then becomes relevant in calculation the earth circumference using the canon and produces 363 x 360 x 1000 = 130680000 / 5280 = 24750 miles against the standardised circumference of 25000 miles exactly 100/99 of it as m/(n-1).

I passed Manu the calculations linking SH to the GP. He said he would get back but as yet have heard nothing from him.

100/99 is included in the calculations.

561 is important as it is base 17 (Thom) as 33 imperial x 17 (Thom) so 1/5 of it is 17 x 11 = 187

89760 / 487 = 480.

This is the evidence that the two bases are deliberately designed into the circumference to produce base 12 x 4.

363 x 100/99* 366.666r x 360 x 1000 = 25000 miles.

I have the GP design as the cubit interpreted using the 'Roman foot' of 12.5 inches incorporating the sekhed to produce the height.

366.66r x 12/12.5 = 352 / 24 = 14.666r x 25 = 36.666r.

100 inches represents one solar day at the GP with a probablity amounting to a certainty.

36300 / 1760 = 20.625 imperial inches plus the ancient metre = 60 inches, plus the foot = 72 plus the lunar representation 28 = 100 inches.

28/12 = 2.333r feet as a radius produces 14.666r circumference.

cheers

Dave

The megalithic metre is 39.60 inches used at SH

39.6 - 39.375 = 0.225 inches

39.6 / 0.225 is 176 and the ancient metre is 175 as Michell discovered within the canon.

We are both using Michell's system.

Thom plus Michell = the GP and SH and the Eclipse.

The foot does not have to be a constant in the equation or the moon unit.

I am not convinced thar the Egyptians knew the SOL but certainly the ancient metre. However I do agree your calculations and now it appears the latitude of the GP gives the SOL apparently!! I have not checked this.

i do know the eclipse year gives the modern equatorial circumference using the canon as 365.222r days. This is another head scratching finding.

As for pi manipulation, there is little doubt the ancients manipulated 22/7 to get to more accurate values of Pi. One caveat is that the numbers must be able to be expressed in Egyptian fractions.

22/7 x 9996/10000 = 31416/10000 or 3.1416 x 3.5 = 8.976 divided ibto 897.6 = 100 at SH.

Edited 4 time(s). Last edit at 17-Jun-18 06:45 by DavidK.

thanks, your SOL calculations led me to look for n/(n-1) links between our findings an Manu supplied the background as the links between the cubit the metre and the foot totalling 72 with the foot constant at 12 the metre plus the cubit are two variables totalling 60.

So the ancient metre you use as 39.375 gives a variable cubit of 20.625 imperial inches x 17.60 or 17600/100 gives 363 solar days at the GP.

The length of the foot then becomes relevant in calculation the earth circumference using the canon and produces 363 x 360 x 1000 = 130680000 / 5280 = 24750 miles against the standardised circumference of 25000 miles exactly 100/99 of it as m/(n-1).

I passed Manu the calculations linking SH to the GP. He said he would get back but as yet have heard nothing from him.

100/99 is included in the calculations.

561 is important as it is base 17 (Thom) as 33 imperial x 17 (Thom) so 1/5 of it is 17 x 11 = 187

89760 / 487 = 480.

This is the evidence that the two bases are deliberately designed into the circumference to produce base 12 x 4.

363 x 100/99* 366.666r x 360 x 1000 = 25000 miles.

I have the GP design as the cubit interpreted using the 'Roman foot' of 12.5 inches incorporating the sekhed to produce the height.

366.66r x 12/12.5 = 352 / 24 = 14.666r x 25 = 36.666r.

100 inches represents one solar day at the GP with a probablity amounting to a certainty.

36300 / 1760 = 20.625 imperial inches plus the ancient metre = 60 inches, plus the foot = 72 plus the lunar representation 28 = 100 inches.

28/12 = 2.333r feet as a radius produces 14.666r circumference.

cheers

Dave

The megalithic metre is 39.60 inches used at SH

39.6 - 39.375 = 0.225 inches

39.6 / 0.225 is 176 and the ancient metre is 175 as Michell discovered within the canon.

We are both using Michell's system.

Thom plus Michell = the GP and SH and the Eclipse.

The foot does not have to be a constant in the equation or the moon unit.

I am not convinced thar the Egyptians knew the SOL but certainly the ancient metre. However I do agree your calculations and now it appears the latitude of the GP gives the SOL apparently!! I have not checked this.

i do know the eclipse year gives the modern equatorial circumference using the canon as 365.222r days. This is another head scratching finding.

As for pi manipulation, there is little doubt the ancients manipulated 22/7 to get to more accurate values of Pi. One caveat is that the numbers must be able to be expressed in Egyptian fractions.

22/7 x 9996/10000 = 31416/10000 or 3.1416 x 3.5 = 8.976 divided ibto 897.6 = 100 at SH.

Edited 4 time(s). Last edit at 17-Jun-18 06:45 by DavidK.

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