Mysteries :
The Official GrahamHancock.com forums

For serious discussion of the controversies, approaches and enigmas surrounding the origins and development of the human species and of human civilization. (NB: for more ‘out there’ posts we point you in the direction of the ‘Paranormal & Supernatural’ Message Board).

This is a quite stunning 'reveal'

Thom's Aubrey using 100 units to a foot is 89760.

divide by 561 to get exactly 160.

5280 /33 = 160 imperial

5440/34 = 160 Thom

89760 / 5280 = 17

89760 / 5440 = 16.5

17 x 16.5 x 2 = 561.

89760/561 x 560 = 89600

obviously 280 x 560 and straight lunar cycle counting with 28 days between each Aubrey circle marker.

The point being unless there is an awareness that n/(n-1) was being used then this unit 561 would not be considered yet it is quite obvious once discovered.

What does 561 do?

It works against the two systems embedded in 89760 being the imperial and Thom's systems.

The imperial is base 33 and Thom base 17

17 x 33 = 561.

By dividing it removes these two bases from 89760 and replaces them with 8 x 7 x 10 =560.

So the lunar counting cycle is revealed.

So units produced using n/(n-1) manipulate and change the prime numbers in the table

base/system

37 Scottish mile = 5920 feet from Edinburgh Castle to Holy Rood House the holy rood is 111 feet

36 English mile x 12/11 = 5760

35 Roman mile = 5600 feet a lunar unit x 5/4 = 7000 / 7 = 1000 weeks

34 Thom = 5440 feet x 5/4 =6800 feet the nodal cycle

33 English = 5280 feet x 5/4 = 6600 the eclipse system 6600/7 = 942.87 weeks or 150 x 44/7

32 Welsh = 5120 feet - all systems are base 32 so this becomes the first system as 32/32

So each number needs to be analysed into its primes.

89760

[numbermatics.com]

it can be seen at once that the two missing primes are 7 and 13 and this is because they are denominators in Thom and imperial pi.

7 x 13 = 91 one season in the Asimov calendar.

So 4 is missing to give one year and 8 is missing to give the 8 year cycle of 2922 -10 days = 8 Asimov astronomical years.

91 x 4 x 8 = 2912 solar days.

2912 x 89760 = 261381120

[numbermatics.com]

2 to the power 10 is being used that is 32 squared x primes from 3 to 17

This analysis is in my book 'The Eclipse'

It is a simple matter to get from 28 days to 29.333r days the eclipse month using n/(n-1) as 4/3

22 x 4/3 = 29.333r x 12 = 352 lunar eclipse year in solar days

21 x 4/3 = 28

so n/(n-1) becomes 22/21

[numbermatics.com]

It is important to understand the structure of each number if base 17 appears then it is Thom.

Michell analyses the uk landscape between the 51st and 52 parallels

51/3 = 17

51/52 x 32 is Thom pi using n/(n-1) inverted

If SH represents 2912 solar days then Brodgar represents 2912 / 0.84 solar days = 3466.666r days 10 lunar yearly cycles based on Thom's analysis on page 47 of his first book.

Edited 6 time(s). Last edit at 12-Jun-18 07:09 by DavidK.

Thom's Aubrey using 100 units to a foot is 89760.

divide by 561 to get exactly 160.

5280 /33 = 160 imperial

5440/34 = 160 Thom

89760 / 5280 = 17

89760 / 5440 = 16.5

17 x 16.5 x 2 = 561.

89760/561 x 560 = 89600

obviously 280 x 560 and straight lunar cycle counting with 28 days between each Aubrey circle marker.

The point being unless there is an awareness that n/(n-1) was being used then this unit 561 would not be considered yet it is quite obvious once discovered.

What does 561 do?

It works against the two systems embedded in 89760 being the imperial and Thom's systems.

The imperial is base 33 and Thom base 17

17 x 33 = 561.

By dividing it removes these two bases from 89760 and replaces them with 8 x 7 x 10 =560.

So the lunar counting cycle is revealed.

So units produced using n/(n-1) manipulate and change the prime numbers in the table

base/system

37 Scottish mile = 5920 feet from Edinburgh Castle to Holy Rood House the holy rood is 111 feet

36 English mile x 12/11 = 5760

35 Roman mile = 5600 feet a lunar unit x 5/4 = 7000 / 7 = 1000 weeks

34 Thom = 5440 feet x 5/4 =6800 feet the nodal cycle

33 English = 5280 feet x 5/4 = 6600 the eclipse system 6600/7 = 942.87 weeks or 150 x 44/7

32 Welsh = 5120 feet - all systems are base 32 so this becomes the first system as 32/32

So each number needs to be analysed into its primes.

89760

[numbermatics.com]

it can be seen at once that the two missing primes are 7 and 13 and this is because they are denominators in Thom and imperial pi.

7 x 13 = 91 one season in the Asimov calendar.

So 4 is missing to give one year and 8 is missing to give the 8 year cycle of 2922 -10 days = 8 Asimov astronomical years.

91 x 4 x 8 = 2912 solar days.

2912 x 89760 = 261381120

[numbermatics.com]

2 to the power 10 is being used that is 32 squared x primes from 3 to 17

This analysis is in my book 'The Eclipse'

It is a simple matter to get from 28 days to 29.333r days the eclipse month using n/(n-1) as 4/3

22 x 4/3 = 29.333r x 12 = 352 lunar eclipse year in solar days

21 x 4/3 = 28

so n/(n-1) becomes 22/21

[numbermatics.com]

It is important to understand the structure of each number if base 17 appears then it is Thom.

Michell analyses the uk landscape between the 51st and 52 parallels

51/3 = 17

51/52 x 32 is Thom pi using n/(n-1) inverted

If SH represents 2912 solar days then Brodgar represents 2912 / 0.84 solar days = 3466.666r days 10 lunar yearly cycles based on Thom's analysis on page 47 of his first book.

Edited 6 time(s). Last edit at 12-Jun-18 07:09 by DavidK.

Sorry, you can't reply to this topic. It has been closed.