Mysteries :
The Official GrahamHancock.com forums

For serious discussion of the controversies, approaches and enigmas surrounding the origins and development of the human species and of human civilization. (NB: for more ‘out there’ posts we point you in the direction of the ‘Paranormal & Supernatural’ Message Board).

Jim

you just posted the solution to the biggest and most perplexing problem of all time and copyrighted it. i hope you are planning to write a book about it? need any help let me know.

This solution (and i have known about it for some time because we have discussed it before and i ended up in the local with a big hangover half way round the world from you), to me suggests that the imperial system and base 100 and base 99 are found inside pi using your solution. The God solution?

This is the universally sacred numerical referencing of Thom and his work at Woodhenge.The version of Pi that comes out of this solution is 22/7 and was used by the ancients but as Jacob says not necessarily as Pi as we know it.

It is the relationship between the circle and square that overrides Pi i think.

A straight line of 12 inches provides the solution. know the side of the square know the circle is what they knew.

The circle is 53.333r inches the (nippur cubit x egyptian pi x 10)

If the nippur cubit is in inches the result is 64 and in feet is 53.333r

But the simple secret is 10/9 that is all you need to know.

10/9, that is all i know, that is all I need to know.

12 x 4 = 48 x 10/9 = 53.333r

So you can pinpoint the azimuth and aim it at any point on the horizon when the design is set out.

The vessica will always be produced, the sign of the fish. it can produce elongated or flattened circles.

As Thom said 'They knew exactly what they were doing'

i know that if my square side is 12 the circle will be 53.333 using 10/9.

What about 100/99 did they use that as well

53.333r /100 x 99 = 52.80 you bet they did and this is where they fooled us.

The foot is a base 100 unit on a base 99 system (the imperial)

5280 / 0.99 = 53333.333r the eclipse system.

the foot is a variable unit in the system but the constant is

using Thom's system the foot is 1.02 imperial feet

5440 / 1.02 = 5333.3333r the constant unit in all systems.

Scottish foot is 1.11 imperial feet

5920 / 1.11 = 5333.333r

5333.333r / 9.87654321 = 540 or 9 x 6 x 10 or 2 x 3 x 3 x 3 x 10.

The thing is they were using this system in full order at Carnac in France circa 5000 BCE and Gobleki?

So who worked it out?

53.333r x 2.75 = 146.666r x 12 = 176 the Egyptians knew it.

Was it discovered through the eclipse rather than your method?

cheers

Dave

you just posted the solution to the biggest and most perplexing problem of all time and copyrighted it. i hope you are planning to write a book about it? need any help let me know.

This solution (and i have known about it for some time because we have discussed it before and i ended up in the local with a big hangover half way round the world from you), to me suggests that the imperial system and base 100 and base 99 are found inside pi using your solution. The God solution?

This is the universally sacred numerical referencing of Thom and his work at Woodhenge.The version of Pi that comes out of this solution is 22/7 and was used by the ancients but as Jacob says not necessarily as Pi as we know it.

It is the relationship between the circle and square that overrides Pi i think.

A straight line of 12 inches provides the solution. know the side of the square know the circle is what they knew.

The circle is 53.333r inches the (nippur cubit x egyptian pi x 10)

If the nippur cubit is in inches the result is 64 and in feet is 53.333r

But the simple secret is 10/9 that is all you need to know.

10/9, that is all i know, that is all I need to know.

12 x 4 = 48 x 10/9 = 53.333r

So you can pinpoint the azimuth and aim it at any point on the horizon when the design is set out.

The vessica will always be produced, the sign of the fish. it can produce elongated or flattened circles.

As Thom said 'They knew exactly what they were doing'

i know that if my square side is 12 the circle will be 53.333 using 10/9.

What about 100/99 did they use that as well

53.333r /100 x 99 = 52.80 you bet they did and this is where they fooled us.

The foot is a base 100 unit on a base 99 system (the imperial)

5280 / 0.99 = 53333.333r the eclipse system.

the foot is a variable unit in the system but the constant is

using Thom's system the foot is 1.02 imperial feet

5440 / 1.02 = 5333.3333r the constant unit in all systems.

Scottish foot is 1.11 imperial feet

5920 / 1.11 = 5333.333r

5333.333r / 9.87654321 = 540 or 9 x 6 x 10 or 2 x 3 x 3 x 3 x 10.

The thing is they were using this system in full order at Carnac in France circa 5000 BCE and Gobleki?

So who worked it out?

53.333r x 2.75 = 146.666r x 12 = 176 the Egyptians knew it.

Was it discovered through the eclipse rather than your method?

cheers

Dave

Sorry, only registered users may post in this forum.