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I think Jim is on to something with fibonacci Pi and radius of the Earth as 7920 miles.
First off there are 7920 inches in 10 chains of 660 feet.
660 feet is 600 saxon feet so a base 60 system.
Fibonacci pi is stated as 3.14181818r
2 Pi r is 7920 x 2 x 3.14161616r = 24883.20
Michell did not use fibonacci Pi but it works with the canon beautifully.
Michell calculated the meridian circumference at 24883.20 miles.
So how does this number work
24883.2 / 144 = 172.8
172.8 / 144 = 1.2 feet
1.2 feet is 14.4 inches.
Does this circumference have the eclipse unit 14.666r in it ?
Convert to inches then divide by 14.666r
24883.2 x 5280 = 131383296
131383296 x 12 = 1576599552
1576599552 / 14.666rr = 107495424
107495424 / 144 = 746496
746496 / 144 = 5184 a familiar unit embedded in 24883.20 the meridonal circumference
[grahamhancock.com]
This circumference 24883.2 miles translates to 364.9536 solar days and a cubit length / 17.6 of 20.736 inches.
Edited 2 time(s). Last edit at 21-Mar-18 11:20 by DavidK.
First off there are 7920 inches in 10 chains of 660 feet.
660 feet is 600 saxon feet so a base 60 system.
Fibonacci pi is stated as 3.14181818r
2 Pi r is 7920 x 2 x 3.14161616r = 24883.20
Michell did not use fibonacci Pi but it works with the canon beautifully.
Michell calculated the meridian circumference at 24883.20 miles.
So how does this number work
24883.2 / 144 = 172.8
172.8 / 144 = 1.2 feet
1.2 feet is 14.4 inches.
Does this circumference have the eclipse unit 14.666r in it ?
Convert to inches then divide by 14.666r
24883.2 x 5280 = 131383296
131383296 x 12 = 1576599552
1576599552 / 14.666rr = 107495424
107495424 / 144 = 746496
746496 / 144 = 5184 a familiar unit embedded in 24883.20 the meridonal circumference
[grahamhancock.com]
This circumference 24883.2 miles translates to 364.9536 solar days and a cubit length / 17.6 of 20.736 inches.
Edited 2 time(s). Last edit at 21-Mar-18 11:20 by DavidK.
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