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Sirfiroth Wrote:

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> Thanks Harte, The Ancient Egyptians did indeed use

> the seked to calculate gradients. We know because

> we have records, G1 is built on a 5 1/2 seked.

> which is a 5 palms + 2 digits run to a rise of 7

> palms which naturally incorporates the pi ratio,

> (4 / (22/7) = 14/11) the rise run of the 5 1/2

> seked. Most assuredly if the Ancient Egyptians had

> been cognizant and used pi they would surely have

> made a note of it somewhere, either in the papyri

> or carved in a obelisk or stele somewhere. Yet,

> there is no recorded record of any form of pi by

> the Ancient Egyptians. Rhind Mathematical Papyrus

> problem #50 demonstrates their method for finding

> the area of a circle which they then used

> extensively in the papyri for many different

> calculations never bothering to use the pi ratio.

> With their methods so clearly spelled out in the

> papyri did they even bother to calculate the

> circumference of a circle? If so, without pi how

> were they able to calculate the circumference of a

> circle?

>

> Regards,

> Jacob

My understanding is that they didn't calculate circumference directly. They estimated using polygonal perimeters.

I should note that for those who don't know or didn't read the link I provided that 22/7 isn't actually "encoded" into the GP. It is the result of mathematical manipulation of the height measure and the perimeter of the base.

The 5-1/2 seked mentioned is 22 fingers "in" for every cubit "up." And a cubit is 7 palms, or 28 fingers. Therefore the actual ratio is 22/28, and the 22/7 comes from dividing the perimeter by 2 in the false numerology of the structure.

Harte

-------------------------------------------------------

> Thanks Harte, The Ancient Egyptians did indeed use

> the seked to calculate gradients. We know because

> we have records, G1 is built on a 5 1/2 seked.

> which is a 5 palms + 2 digits run to a rise of 7

> palms which naturally incorporates the pi ratio,

> (4 / (22/7) = 14/11) the rise run of the 5 1/2

> seked. Most assuredly if the Ancient Egyptians had

> been cognizant and used pi they would surely have

> made a note of it somewhere, either in the papyri

> or carved in a obelisk or stele somewhere. Yet,

> there is no recorded record of any form of pi by

> the Ancient Egyptians. Rhind Mathematical Papyrus

> problem #50 demonstrates their method for finding

> the area of a circle which they then used

> extensively in the papyri for many different

> calculations never bothering to use the pi ratio.

> With their methods so clearly spelled out in the

> papyri did they even bother to calculate the

> circumference of a circle? If so, without pi how

> were they able to calculate the circumference of a

> circle?

>

> Regards,

> Jacob

My understanding is that they didn't calculate circumference directly. They estimated using polygonal perimeters.

I should note that for those who don't know or didn't read the link I provided that 22/7 isn't actually "encoded" into the GP. It is the result of mathematical manipulation of the height measure and the perimeter of the base.

The 5-1/2 seked mentioned is 22 fingers "in" for every cubit "up." And a cubit is 7 palms, or 28 fingers. Therefore the actual ratio is 22/28, and the 22/7 comes from dividing the perimeter by 2 in the false numerology of the structure.

Harte

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