Answer :

Given: 3x + 4y 12

Consider: 3x + 4y = 12

Now draw a solid line 3x + 4y = 12 in the graph (∵3x + 4y = 12 is included in the given question)

Now Consider 3x + 4y 12

Select a point (0,0)

⇒ 3 × (0) + 4 × (0) 12

⇒ 012 (this is true)

∴ Solution region of the given inequality is below the line 3x + 4y = 12. (That is origin is included in the region)

The graph is as follows:

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