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Hey Hendrik,

Long time eh! I haven't thought about the octohedron it since the last time I had a conversation with Stephen (aka magisterchessmutt) about the it some five years ago, I had saved it to hard drive but lost it when the hard drive crashed. But if I remember correctly it was decided the cuboctohedron an Archimedean solid could possibly be a better model dealing Earth-Moon-Sun cycles. Modified Cuboctohedron Pictured below.

Composed of 4 hexagons set at 60 degrees, creating a structure with 8 triangular faces, 6 square faces with 12 identical vertices, with 2 triangles and 2 squares meeting at each, and 24 identical edges equal to a radius of a spherical enclosure, each separating a triangle from a square. The identical edges equal to the radius of a spherical enclosure.

I will try and reconstruct what Stephen and I talked about, which shouldn't take more than a day or two.

Apologizing in advance but the Ancient Egyptian measurements don't translate into metric very well so I use British Imperial units. By using the cubit, palm, digit, inch, foot, yard and mile everything seems to flow together much easier.

You wrote: 1min. of arc = 1 nautical mile / 1.852 km 1 nautical mile = 1/60 degree

1° arc = 364953 3/5 feet, 1 nautical mile = 6082 14/25 feet, with 1/8 being equal to the South Side Base G1 760 8/25 feet.

19008/25 feet, 9123 21/25 inches (aka 9123.84 inches within 6/100 inch of Petrie's measure of 9123.9 inches for the South side socket base). also equating to 228096/25 inches which is exactly 440 G2 Sarcophagus cubits of 2592/125 inches aka 20.736 inches.

You wrote: 1° longitude = 60 nautical miles Earth's circumference 21 639 nautical miles / 40 075km

Earth mean circumference 24883 1/5 statute miles, 131383296 feet, 21600 nautical miles 1 minute of arc = 1 nautical mile.

131383296 / 86400 = 1520 16/25 feet = one second rotation = 15 arc seconds.

One minute Earth rotation = 91238 2/5 feet x 12

<snip>

Jacob

Long time eh! I haven't thought about the octohedron it since the last time I had a conversation with Stephen (aka magisterchessmutt) about the it some five years ago, I had saved it to hard drive but lost it when the hard drive crashed. But if I remember correctly it was decided the cuboctohedron an Archimedean solid could possibly be a better model dealing Earth-Moon-Sun cycles. Modified Cuboctohedron Pictured below.

Composed of 4 hexagons set at 60 degrees, creating a structure with 8 triangular faces, 6 square faces with 12 identical vertices, with 2 triangles and 2 squares meeting at each, and 24 identical edges equal to a radius of a spherical enclosure, each separating a triangle from a square. The identical edges equal to the radius of a spherical enclosure.

I will try and reconstruct what Stephen and I talked about, which shouldn't take more than a day or two.

Apologizing in advance but the Ancient Egyptian measurements don't translate into metric very well so I use British Imperial units. By using the cubit, palm, digit, inch, foot, yard and mile everything seems to flow together much easier.

You wrote: 1min. of arc = 1 nautical mile / 1.852 km 1 nautical mile = 1/60 degree

1° arc = 364953 3/5 feet, 1 nautical mile = 6082 14/25 feet, with 1/8 being equal to the South Side Base G1 760 8/25 feet.

19008/25 feet, 9123 21/25 inches (aka 9123.84 inches within 6/100 inch of Petrie's measure of 9123.9 inches for the South side socket base). also equating to 228096/25 inches which is exactly 440 G2 Sarcophagus cubits of 2592/125 inches aka 20.736 inches.

You wrote: 1° longitude = 60 nautical miles Earth's circumference 21 639 nautical miles / 40 075km

Earth mean circumference 24883 1/5 statute miles, 131383296 feet, 21600 nautical miles 1 minute of arc = 1 nautical mile.

131383296 / 86400 = 1520 16/25 feet = one second rotation = 15 arc seconds.

One minute Earth rotation = 91238 2/5 feet x 12

<snip>

Jacob

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