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'The applicable cubit length is 20 34/55, (20.6181818 inches) based on the arc second circle. which is 3024/3025 to the cubits you used. 20 34/55 / (3024/3025) = 20 5/8 '
this aligns with Hugh Franklin's cubit calculation as 20.61136364 ( The HFC )Hugh Franklin Cubit.
[www.megalithic.co.uk]
A 20.6181818181818 minus B 20.61136364 = C 0.006818182
a/c = 3024 b/c = 3023 x 12 = 36276 inches for the total GP base this is 755.75 feet for each side as close to Petrie's measurement as it is possible to get and in agreement with the Encyclopedia Brittanica.
Edited 1 time(s). Last edit at 28-Dec-17 19:36 by DavidK.
this aligns with Hugh Franklin's cubit calculation as 20.61136364 ( The HFC )Hugh Franklin Cubit.
[www.megalithic.co.uk]
A 20.6181818181818 minus B 20.61136364 = C 0.006818182
a/c = 3024 b/c = 3023 x 12 = 36276 inches for the total GP base this is 755.75 feet for each side as close to Petrie's measurement as it is possible to get and in agreement with the Encyclopedia Brittanica.
Edited 1 time(s). Last edit at 28-Dec-17 19:36 by DavidK.
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