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Hi Cladking,

I intend to help and address your 4 1/2" rope needs, and why I feel you would not require anything on that scale. By using the tools I have provided, you will arrive at a realistic number. Please tell me if you're are using an Incline Plain, or not, and the amount of weight you are attempting to lift. These Links should enable you to to obtain an accurate figure.

Ref: Water Funiculars

[www.youtube.com]

Though these are people being lifted, (weight/mass) the principle remains the same.

Objective: To understand how much water is required to move 1 stone up on an 4.6 degree (Causeway) incline plain. Additionally, the ropes MBG (minimum breakage load). All of which is based on the mass (barge) COF (coefficient of friction).

Open this link: [hyperphysics.phy-astr.gsu.edu] And view the example below.

First, it is in Kg. and we will need to use that setting, as it doesn't work with lbs.

Understanding that a Mass of (1134Kg. = 2,500lbs., or the average weight of 1 Pyramid stone.

So, in the order from top to bottom, filling in the boxes, you would enter...

1. 4.6 (angle of incline)

2. 1133Kg (1 stone) or 2,500lbs.

3. 1222..... OK, how you arrive at this number, is by simply changing the weight in the #5, acceleration box. The final number will be very close to 0. Ref: Reaching .002 is sufficient. This is the dividing line. The point where adding any more weight will cause the barges to move. Accelerate. You are not trying to estimate the Acceleration rate, though it will show you at what point, the added weight will overcome the Static (Mass) load. And, by doing this, you will establish the rope size needed.

4. Place 1 in the friction coefficient box.

Now in the 2nd paragraph, the tension in Rope. Note it is in Newtons. You will need to change that into Kg, and/or Lbs. depending on your location. The example is listing 11966.5 Newtons, which = (2690.18) pound-force. This is the force, your rope would need to endure, to pull the listed weight up the 4.6 incline.

Rope: [www.e-rigging.com] As we only need 2,690.18 Lbs of force, a 5/8" rope would be more than enough to exceed the Minimum Breaking Load (MBL): 3960 lbs2" rope: [www.paracordplanet.com]

Link for converting Kg. to Lbs.

[www.google.com] q=Kg+%3D+lbs&rlz=1C5CHFA_enUS802US802&oq=Kg+%3D+lbs&aqs=chrome.0.69i59j6.5544j0j8&sourceid=chrome&ie=UTF-8ink

Converting Newtons to Lbs. [www.unitconverters.net]

1 sq. ft. of Water = 62.43 pounds: [www.google.com]

1259Kg. = 2755.78lbs. divided by 62.43lbs. (sq. ft. of water) = 44.142sq,ft. The Barges can hold much more than that amount. Barges are 28' x 14' x 5' = 1,960 sq. ft. Remember that barge size will be handling 12 stones.

Hopefully, I got everything correct. I will be updating... Please feel free to ask questions, and inform me if any links are not working properly. I will be reviewing this again in the Morning. Once you understand these tools, I will be adding more components, and conclude with an illustration, based on there results.

This second picture is for 12 stones. A minimum breakage load of 32,296lbs.

1.5” - 38.1 mm - 16,650 lbs. x 2 = 33,300 (Two 1 1/2" ropes works).

Edited 1 time(s). Last edit at 24-Mar-20 21:22 by Steve Clayton.

I intend to help and address your 4 1/2" rope needs, and why I feel you would not require anything on that scale. By using the tools I have provided, you will arrive at a realistic number. Please tell me if you're are using an Incline Plain, or not, and the amount of weight you are attempting to lift. These Links should enable you to to obtain an accurate figure.

Ref: Water Funiculars

[www.youtube.com]

Though these are people being lifted, (weight/mass) the principle remains the same.

Objective: To understand how much water is required to move 1 stone up on an 4.6 degree (Causeway) incline plain. Additionally, the ropes MBG (minimum breakage load). All of which is based on the mass (barge) COF (coefficient of friction).

Open this link: [hyperphysics.phy-astr.gsu.edu] And view the example below.

First, it is in Kg. and we will need to use that setting, as it doesn't work with lbs.

Understanding that a Mass of (1134Kg. = 2,500lbs., or the average weight of 1 Pyramid stone.

So, in the order from top to bottom, filling in the boxes, you would enter...

1. 4.6 (angle of incline)

2. 1133Kg (1 stone) or 2,500lbs.

3. 1222..... OK, how you arrive at this number, is by simply changing the weight in the #5, acceleration box. The final number will be very close to 0. Ref: Reaching .002 is sufficient. This is the dividing line. The point where adding any more weight will cause the barges to move. Accelerate. You are not trying to estimate the Acceleration rate, though it will show you at what point, the added weight will overcome the Static (Mass) load. And, by doing this, you will establish the rope size needed.

4. Place 1 in the friction coefficient box.

Now in the 2nd paragraph, the tension in Rope. Note it is in Newtons. You will need to change that into Kg, and/or Lbs. depending on your location. The example is listing 11966.5 Newtons, which = (2690.18) pound-force. This is the force, your rope would need to endure, to pull the listed weight up the 4.6 incline.

Rope: [www.e-rigging.com] As we only need 2,690.18 Lbs of force, a 5/8" rope would be more than enough to exceed the Minimum Breaking Load (MBL): 3960 lbs2" rope: [www.paracordplanet.com]

Link for converting Kg. to Lbs.

[www.google.com] q=Kg+%3D+lbs&rlz=1C5CHFA_enUS802US802&oq=Kg+%3D+lbs&aqs=chrome.0.69i59j6.5544j0j8&sourceid=chrome&ie=UTF-8ink

Converting Newtons to Lbs. [www.unitconverters.net]

1 sq. ft. of Water = 62.43 pounds: [www.google.com]

1259Kg. = 2755.78lbs. divided by 62.43lbs. (sq. ft. of water) = 44.142sq,ft. The Barges can hold much more than that amount. Barges are 28' x 14' x 5' = 1,960 sq. ft. Remember that barge size will be handling 12 stones.

Hopefully, I got everything correct. I will be updating... Please feel free to ask questions, and inform me if any links are not working properly. I will be reviewing this again in the Morning. Once you understand these tools, I will be adding more components, and conclude with an illustration, based on there results.

This second picture is for 12 stones. A minimum breakage load of 32,296lbs.

1.5” - 38.1 mm - 16,650 lbs. x 2 = 33,300 (Two 1 1/2" ropes works).

Edited 1 time(s). Last edit at 24-Mar-20 21:22 by Steve Clayton.

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