As demonstrated by problem #10 of the Moscow Mathematical Papyrus , in their own indomitable way, show a circle area x 2 equals the surface area of a hemisphere, therefore a circle area x 4 equals the surface are of a hemisphere.
Problem 50 formula applied to the 4 1/2 diameter of MMP 10 (4 1/2 x 8/9)^2 = 16 sq area of a circle
Problem 10 states 9 x 8/9 x 8/9 x 4 1/2 = 32 which equals twice the circle area.
The fact is in any circle with a circumscribed square the ratio between the square and circle area or the circumference and perimeter is the 5 1/2 seked rise run of 14/11 as found in G1 and Meydum pyramids. In G1 and Meydum where the perimeter and circumference are equal, but the square and circle areas of the two constructs still maintain a 14/11 ratio to one another.
i.e. 440^2 = 193600 area square cubits, perimeter 1760 cubits (440 x4)
193600 x 14/11 = 2464000 area circle sq cubits, circumference 1760 cubits, radius 280 cubits.
Circle circumference x 1/2 the radius = circle area.
What ever we can do with pi they could do with the 5 1/2 seked yielding pi like results in the form of 22/7. Reiterating and as stated many times before, there is no mention of pi anywhere in the Ancient Egyptian archives, but we do find multiple references to the 5 1/2 seked, and the square and circle. The problem is, everyone seems to be intent on proving the Ancient Egyptians used pi while ignoring their demonstrated use of the the 5 1/2 seked.