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Hi Jim

It seems perfectly valid to use 891 in the context of the Aubrey if you imagine it as a series of concentric circles culminating in 897.60.

your circle is 135 x 6.6 and the Aubrey external circ to the outsides of the postholes is 136 x 6.6 or 272 x 3.3.This is the megalithic metre x the Saxon or Indus valley yard.

The diameter is 283.5 imperial feet.Heath uses 283.60 and this is posthole centre to posthole centre so postholes radius is 1 imperial foot.

285.6-283.5 = 2.1 feet 285.6 / 2.1 = 136 Thom again and obviously 22/7.

I can see whrer you are going with this heading towards 29.53064 or something silmilar.

have you thought about this?

29.333r x 39.60 = 1161.60 inches this is 96.80 feet

1161.6 / 6.6 = 176.

29.5333r x 39.60 = 1169.52 / 12 = 97.46

When I read Rollrights it was area that rang a bell because i had never seen area included in astronomoical analysis ever. and it is imperial area so a double whammy.

What i am doing at the mo is translating numbers using what i believe to be the system base unit as 1/9 = 0.1111r

14.666666666666666r / 0.1111r = 1320 as the starting point.This gells our approaches.

365.222r is the Solar Eclipse year 365.222r / 0.1111r = 32870.

366.666 = 33000 this is base 33 the imperial system.

This creates a concentric circle set up but the GP is squares, meaning area is significant, so Pythagoras comes into play as the side squared and the right angled triangle.

Look at 256/81

1.333r x 1.333r = 1.777r

1.777r x 1.777r = 3.160493827 Egyptian pi!!

This is 1.333r x 1.333r x 1.333r x 1.333r

1.333r / 0.111r = 12

1.777r / 0.111r = 16

12 x 12 x 12 x 12 = 20736

16 x 16 = 256

20736 / 256 = 81

256/81 = egyptian pi

Any infinire repeating number can be translated

362.6666666666666666666666666 suggests Thom at the GP

362.66 / 0.111r = 3264 the megalithic yard in inches.

the evidence suggests the Egyptians were very familiar with 12 x 1.11111r = 13.333r = 10 x 4/3.

The GP base can be translated to 1760 / 4 x 3 = 1320

Oviously i would never have looked at rhind 50 without seeing your analysis but it is very significant.

My preferred analysis of the GP base is 1320/0.99 = 1333.333r as a constant because if this is area the square root is based on root 4/3 and this is Hugh Franklin's analysis althogh he did not realise this. He always had it as root 3 divided by 2.

This is my analysis of the GP design based on Cole's outputs.

base side root 4/3 = 1.3333r base area

height 1.4666r

slope 1.8666r

Pythagoras gives

1.4666r squared = 2.151111111

1.8666r squared = 3.484444444

difference is 1.3333r exactly

base side is root 4/3 and Hugh has this times real pi = 9069 x 4 inches.

the only problem is the sekhed angle is not 51.84 it is 51.79

but 1.8666r/1.4666r is the sekhed.

copyright DTK

Edited 1 time(s). Last edit at 17-Jul-18 05:21 by DavidK.

It seems perfectly valid to use 891 in the context of the Aubrey if you imagine it as a series of concentric circles culminating in 897.60.

your circle is 135 x 6.6 and the Aubrey external circ to the outsides of the postholes is 136 x 6.6 or 272 x 3.3.This is the megalithic metre x the Saxon or Indus valley yard.

The diameter is 283.5 imperial feet.Heath uses 283.60 and this is posthole centre to posthole centre so postholes radius is 1 imperial foot.

285.6-283.5 = 2.1 feet 285.6 / 2.1 = 136 Thom again and obviously 22/7.

I can see whrer you are going with this heading towards 29.53064 or something silmilar.

have you thought about this?

29.333r x 39.60 = 1161.60 inches this is 96.80 feet

1161.6 / 6.6 = 176.

29.5333r x 39.60 = 1169.52 / 12 = 97.46

When I read Rollrights it was area that rang a bell because i had never seen area included in astronomoical analysis ever. and it is imperial area so a double whammy.

What i am doing at the mo is translating numbers using what i believe to be the system base unit as 1/9 = 0.1111r

14.666666666666666r / 0.1111r = 1320 as the starting point.This gells our approaches.

365.222r is the Solar Eclipse year 365.222r / 0.1111r = 32870.

366.666 = 33000 this is base 33 the imperial system.

This creates a concentric circle set up but the GP is squares, meaning area is significant, so Pythagoras comes into play as the side squared and the right angled triangle.

Look at 256/81

1.333r x 1.333r = 1.777r

1.777r x 1.777r = 3.160493827 Egyptian pi!!

This is 1.333r x 1.333r x 1.333r x 1.333r

1.333r / 0.111r = 12

1.777r / 0.111r = 16

12 x 12 x 12 x 12 = 20736

16 x 16 = 256

20736 / 256 = 81

256/81 = egyptian pi

Any infinire repeating number can be translated

362.6666666666666666666666666 suggests Thom at the GP

362.66 / 0.111r = 3264 the megalithic yard in inches.

the evidence suggests the Egyptians were very familiar with 12 x 1.11111r = 13.333r = 10 x 4/3.

The GP base can be translated to 1760 / 4 x 3 = 1320

Oviously i would never have looked at rhind 50 without seeing your analysis but it is very significant.

My preferred analysis of the GP base is 1320/0.99 = 1333.333r as a constant because if this is area the square root is based on root 4/3 and this is Hugh Franklin's analysis althogh he did not realise this. He always had it as root 3 divided by 2.

This is my analysis of the GP design based on Cole's outputs.

base side root 4/3 = 1.3333r base area

height 1.4666r

slope 1.8666r

Pythagoras gives

1.4666r squared = 2.151111111

1.8666r squared = 3.484444444

difference is 1.3333r exactly

base side is root 4/3 and Hugh has this times real pi = 9069 x 4 inches.

the only problem is the sekhed angle is not 51.84 it is 51.79

but 1.8666r/1.4666r is the sekhed.

copyright DTK

Edited 1 time(s). Last edit at 17-Jul-18 05:21 by DavidK.

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