Mysteries :  The Official GrahamHancock.com forums
For serious discussion of the controversies, approaches and enigmas surrounding the origins and development of the human species and of human civilization. (NB: for more ‘out there’ posts we point you in the direction of the ‘Paranormal & Supernatural’ Message Board). 
Welcome! Log InRegister
Since my theory ( that of hiding one system inside another using to different units of length) allows all cubits between 20 inches and 20.8333r inches to fall into the range, there is no trap to fall into.

The idea is the cubit as 20.8333r inches will never fit into the window identified by Petrie's measurements it is too large if the foot of 12 inches is used.

however if the foot of 12.5 inches is used the cubit then becomes 20.8333r x 12 / 12.5 = 20

20 x 17.60 = 352.

So the variable foot in inches will produce a range of values between 352 and 366.666r, alternatively the canon can be used with the foot a constant value.

To work out solar days just multiply the cubit in inches by 17.60 so 20.75 = 365.20

365.2 /249 x 250 = 366.666r x 360 x 1000 = 132000000.

This is the system

Incidentally 22/7 x 2499/2500 = 3.1416. 3.1416 / 3.5 = 0.8976 onethousandth of the Aubrey circle circumference taht contains both the megalithic yard and the megalithic metre.

So the 25000 baseline has an effect of the value of pi being used just as jim is pointing out using 3.1418181818r fibonacci pi. All part of the same system.

Also using the canon the metre is produced using the sacred baseline analysis.

132000000 x 39.37/39.6 ( subsituting the modern metre for the ancient one). = 1574800000 imperial inches divided by 40000000 = 39.37 using the canon of ancient measure.

364.537037 solar days are represented multiply this by 10.8 to get a shock!!

Multiply 366.666r by 10.8 to get another!!

Solar days by 10.8 gives metres.

The ancient metre is 39375 / 108 = 364.5833333 a unit regularly used by Rodzzz and Magisterchessmut uses the ancient metre to great effect and has put many years of study into these systems.

I still don't believe they knew the SOL despite the evidence.



Edited 3 time(s). Last edit at 19-Jun-18 11:47 by DavidK.

Options: ReplyQuote


Subject Views Written By Posted
Understanding Michell's Canon and Thom using n/(n-1) 785 DavidK 10-Jun-18 09:11
The n/(n-1) ancient systems 119 DavidK 11-Jun-18 06:24
the ancients are laughing at us 139 DavidK 11-Jun-18 06:57
Stonehenge using 561/560 134 DavidK 12-Jun-18 06:25
Re: Stonehenge using 561/560 138 magisterchessmutt 16-Jun-18 06:26
Re: Stonehenge using 561/560 117 DavidK 17-Jun-18 06:27
Re: Stonehenge using 561/560 144 Manu 17-Jun-18 17:04
Re: Stonehenge using 561/560 118 DavidK 18-Jun-18 12:34
Re: Stonehenge using 561/560 108 rodz111 18-Jun-18 19:02
Re: Stonehenge using 561/560 102 Manu 18-Jun-18 19:56
Re: Stonehenge using 561/560 121 DavidK 18-Jun-18 22:13
Re: Stonehenge using 561/560 114 Manu 19-Jun-18 03:19
Re: Stonehenge using 561/560 113 DavidK 19-Jun-18 05:38
Re: Stonehenge using 561/560 96 Manu 19-Jun-18 07:04
Re: Stonehenge using 561/560 105 DavidK 19-Jun-18 10:42
Re: Stonehenge using 561/560 134 Manu 19-Jun-18 18:11
Re: Stonehenge using 561/560 194 DavidK 20-Jun-18 19:12
Understanding “n/n-1” 124 Dr. Troglodyte 11-Jun-18 16:50
Re: Understanding “n/n-1” 132 DavidK 11-Jun-18 18:35
Re: Understanding Michell's Canon and Thom using n/(n-1) 280 rodz111 12-Jun-18 19:48
Re: Understanding Michell's Canon and Thom using n/(n-1) 115 DavidK 13-Jun-18 07:08
Re: Understanding Michell's Canon and Thom using n/(n-1) 125 DavidK 13-Jun-18 07:30
GP perimeter using n/(n-1) 131 DavidK 13-Jun-18 13:38
The sekhed using n/(n-1) 145 DavidK 13-Jun-18 09:14
Re: Understanding Michell's Canon and Thom using n/(n-1) 131 Sirfiroth 19-Jun-18 00:17
Re: Understanding Michell's Canon and Thom using n/(n-1) 110 DavidK 19-Jun-18 20:17
Re: Understanding Michell's Canon and Thom using n/(n-1) 110 Sirfiroth 20-Jun-18 03:12


Sorry, only registered users may post in this forum.