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Hi Rodz

thanks for choosing the cubit of 20.736 inches because the canon produces the circumference from the cubit using the GP design

20.736 x 17.6 = 364.9536 x 360 x 1000 = 131383296 / 5280 = 24833.20 imperial miles.


17.6 is actually 1760/100 as 100 inches represents one solar day at the GP.


Using n/(n-1) (208.36 instead of 207.36 )
the cubit becomes 20.836

20.836 x 17.6 = 366.7136 x 360 x 1000 = 132016896 / 5280 = 25003.2

25003.2 - 24883.2 = 120 miles


so 0.1 of a cubit produces 120 miles difference in the circumference so one cubit inch produces 1200 miles.


so 20.8333r cubit inches produces a 25000 mile standardised circumference


20.8333r x 17.6 = 366.666r x 360 x 1000 = 132000000 / 5280 = 25000 imperial miles.


So to get to the cubit length choose the number of solar days you want and multiply it by 20.8333r / 366.666r.

For example 365.2 days gives a cubit of 20.75 inches.

To apply n/(n-1) between two numbers take the smaller from the larger and divide the result into the larger then take one from the result


20.8333r - 20.75 = 0.08333r


20.8333r / 0.08333r = 250 less one is 249.


very revealing as 366.666r - 365.2 = 1.4666r one tenth of the eclipse unit produced using 250/249 against the standardised circumference.


Michell discovered a very powerful system of ancient measure - it is an eclipse prediction system and also the imperial system and the design of the GP appears to work against its sliding scale, 100 imperial inches representing one solar day within the design.

I think Piazzi Smith originally suggested this but used the pyramid inch of 1.0011 inches because he wanted to get to 365.242 solar days. This 0.0011 adjustment is not requited if Michell's canon is used..

The hardest thing to visualise is that number one is actually (39.60 x 2.525252525r)/100 or (2.5 x 40)/100 ad infinitum and this is the GP design, an infinite interpretation of number one. (132000000 / 1.32) = 1000000/1000000 = 1)


39.60 is not 39.60 it is (40 - 0.4)


40/0.4 = 100/100 = 1


39.60 / 0.4 = 99


39.60 inches is the megalithic metre used in the design of SH

897.60 feet x 12 = 10771.20 inches / 39.60 = 272 Thom's unit.

When you look at 39.60 see 99 and 40 see 100

What you are looking at is not what you are seeing it is all a megalithic mirage based on n/(n-1)



Edited 1 time(s). Last edit at 13-Jun-18 07:23 by DavidK.

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Subject Views Written By Posted
Understanding Michell's Canon and Thom using n/(n-1) 751 DavidK 10-Jun-18 09:11
The n/(n-1) ancient systems 113 DavidK 11-Jun-18 06:24
the ancients are laughing at us 133 DavidK 11-Jun-18 06:57
Stonehenge using 561/560 129 DavidK 12-Jun-18 06:25
Re: Stonehenge using 561/560 130 magisterchessmutt 16-Jun-18 06:26
Re: Stonehenge using 561/560 111 DavidK 17-Jun-18 06:27
Re: Stonehenge using 561/560 135 Manu 17-Jun-18 17:04
Re: Stonehenge using 561/560 112 DavidK 18-Jun-18 12:34
Re: Stonehenge using 561/560 103 rodz111 18-Jun-18 19:02
Re: Stonehenge using 561/560 98 Manu 18-Jun-18 19:56
Re: Stonehenge using 561/560 99 DavidK 18-Jun-18 22:13
Re: Stonehenge using 561/560 106 Manu 19-Jun-18 03:19
Re: Stonehenge using 561/560 107 DavidK 19-Jun-18 05:38
Re: Stonehenge using 561/560 90 Manu 19-Jun-18 07:04
Re: Stonehenge using 561/560 102 DavidK 19-Jun-18 10:42
Re: Stonehenge using 561/560 126 Manu 19-Jun-18 18:11
Re: Stonehenge using 561/560 181 DavidK 20-Jun-18 19:12
Understanding “n/n-1” 119 Dr. Troglodyte 11-Jun-18 16:50
Re: Understanding “n/n-1” 121 DavidK 11-Jun-18 18:35
Re: Understanding Michell's Canon and Thom using n/(n-1) 265 rodz111 12-Jun-18 19:48
Re: Understanding Michell's Canon and Thom using n/(n-1) 105 DavidK 13-Jun-18 07:08
Re: Understanding Michell's Canon and Thom using n/(n-1) 113 DavidK 13-Jun-18 07:30
GP perimeter using n/(n-1) 121 DavidK 13-Jun-18 13:38
The sekhed using n/(n-1) 139 DavidK 13-Jun-18 09:14
Re: Understanding Michell's Canon and Thom using n/(n-1) 125 Sirfiroth 19-Jun-18 00:17
Re: Understanding Michell's Canon and Thom using n/(n-1) 96 DavidK 19-Jun-18 20:17
Re: Understanding Michell's Canon and Thom using n/(n-1) 107 Sirfiroth 20-Jun-18 03:12


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