Here is the main detail that has gotten the Internet's attention:
Speed of light in a vacuum is 299,792,458 meters per second.
And the line of latitude, 29.9792458 degrees north of the equator, runs through the location of the Great Pyramid.
How improbable is this? In order to imagine a random test, we start with the planet and the prevailing global latitude-longitude grid. With no regard for where land ends and the ocean begins, imagine the Great Pyramid being dropped to Earth, from any angle, time and time again, so that in the VERY long run, such trials will have the GP landing evenly all over the planet. This is exactly what the laws of random distribution predict, when "all things are equal". In the first part of this post I will presume that the GP lands as it currently is, basically perfectly aligned to true north, east and west...
1. The main question most people as (without ever following up) is "what are the odds" that the GP will randomly appear "29.9792458 degrees north of the equator?"
And this turns out to be the WRONG question.
Think about this: Surely people would mention the light speed correlation if the GP turned out to be 29.9792458 degrees south of the equator. So, in fact there are at least two ways that the GP could provide this kind of hit with our grid current system. This is the most relevant measure. People fixate on the particular outcome, without asking if other 'comparable' outcomes are possible.
29.9792458 degrees north of the equator
29.9792458 degrees south of the equator.
Looking closer, one clearly sees that 2.99792458 degrees north and south can be also accommodated by our system.
So, in all, there would be four scenarios that people would very likely bring up the GP's light-speed-in-meters correlation.
3. Back to our test. What are the chances that the GP would land on any of our 4 light-friendly lines?
Step One: First, we note that the GP is about 755 feet wide north-to-south.
Next, the distance from North to South pole is est 12500 miles which converts to about 65,000,000 total feet. That's 65 million feet compared to the GP's 755 total feet at the sides. So, the distance from pole to pole consists of about 87,500 755-foot GP-like segments.
There are 4 chances in 87k that the GP would fall over one of these lines, which reduces to a 1-in-22k chance expectation.
Next, by the same reasoning, we have another 4 chances to hit a light-speed correlation, when considering longitude - 29.9792458 degrees west of the equator, 2.99792458 degrees east of the equator. etc. etc.
Since this is a sketch, I will assume that the circumference of the earth is the same as at the poles. BEing more specific will only increase the improbability, since the circumference is bigger, and I want to be as conservative as possible.
And so, when long and lat are considered, one has 8 chances in about 87,000, or a 1-in-11,000 overall odds. Translation, under controlled random conditions we can expect the GP would land over a light speed lines about once every 11,000 times.
Update - Jan 25-19. As mentioned, these estimations are based on the GP landing as it is now, almost perfectly aligned north to south and east to west. If we allow the GP to land any which way, then the maximum diagonal offset lowers our improbability.
Let's say the diagonal base of the GP, from corner to corner, is about 1070 feet (vs est 755 feet corner to corner vertical and horizontal. At this rate, there will 'only' be about 62,000 such diagonal segments from pole to pole, and about the same going east to west, down from 87,000 segments when the 755-foot sides are our working standard.
With 8 chances to hit a light-speed line, the overall improbability of how the GP aligns falls from 1-in-11,000 to about 1-in-7700.
This is far as I can drill down, and our real-life outcome is about twice as rare as Poker's Four of a Kind, a 1-in-4,164 kind of event, where Chance prevails. .
Edited 13 time(s). Last edit at 25-Jan-19 23:22 by Poster Boy.