almost heretical to say those things on this post but i agree with you, welcome to the club.
Great name by the way groove to 10/9 man the unit of infinite oneness, think about it for long enough and you might learn how to levitate yourself. The UOIO.
The Egyptians knew all there is to know about the relationship between the square the cube and the circle and perfect sphere and everythimg in between using Pi culminating in 4/3 x pi to the power 4 or so it would seem based on the evidence posted on this site. They used Pi as 22/7 in one incarnation of it and it works with the imperial system which is a base 11 system.
To understand these systems you have to think in a heavenly way in particular focus on the moon man, try not to howl.
The cubit is 7 units then x 4 = 28. The cubit rules the moon. To get to Egyptian Pi you have to put base 11 on top of base 7 and this is 88/28 to give Pi as 22/7.
Intersetingly the GP using the sekhed 14/11 works as perimeter 1760 units height 280 being 2 x 22/7.
So it is not difficult to find 22/7 using egyptian maths.
Using the Egyptian method of calculating the area of a circle.
100.0000 imperial inches representing 1 solar days
11.1111 one ninth of this
88.8889 Egyptian method of calculating circle area using 8/9 diameter
7901.2346 square imperial inches
800.0000 units of 9.87654321 square inches
3.1605 Version of Pi being used 3.160493827 This is 256/81
33.3333 imperial inches representing 0.333333333 solar days
3.7037 one ninth of this
29.6296 Egyptian method of calculating circle area using 8/9 diameter
877.9150 square imperial inches
88.8889 units of 9.87654321 square inches
125.0000 imperial inches representing 1.25 solar days
13.8889 one ninth of this
111.1111 Egyptian method of calculating circle area using 8/9 diameter
12345.6790 square imperial inches
1250.0000 units of 9.87654321 square inches
So where is 22/7 in all of this?
The UOIO is in there as you can see but it works with 100/99
1.02030405060708000000 as the area of the square 100/99 squared.
The circle area and the square are is 88.8888888r and this is 9 units of 9.87654321
To get to 22/7 the secret system has to be unlocked
28 the cubit has to be multipled by 100/99 to give 28.282828282828r
88.888888r / 28.282828282r = 22/7.
9.87654321 is babylonian pi x egyptian pi producing 9.87654321 a fair representation of Pi squared althogh both numbers are way off Pi as 3.125 x 256/81.
What this leads to is the use of Pi as the radius of a sphere giving the equation for the perfect sphere as Pi to the power 4 x 4/3.
The solution to this thorny problem has been produced on this website by Jim Wakefield but is so far out no one geys it, or wants to get it more like.It is the most amazing calculation i have ever seen in my life because it produces the imperial system numerically and the legth of the foot just happens to be a geodetic unit of length where 132000000 feet is 25000 miles and 24900 or 25000-100 is the equatorial circumference.
The Eclipse unit within this system is 14.666r imperial feet or 176 imperial inches / 56 = 22/7.
Show this to your Math professors and tell them there is a solution to Plimton 322 using Egyptian math.
100 x 100 / 99 / 99 = 10000/9801 and how important is this number in understanding Pi?
9801/9800 now that is really something.
I have written an 'e-book' available on Amazon 'Stonehenge The Eclipse', I think you will get it if you read it. The solution is for mathematicians and scientists really.One of the numbers in the solution is 1001. This is 2.75 periods of 364 days.
A version of Pi in the book is 6800/1733.333r. This work's with professor Thom's megalithic yard 2.72 imperial feet.
6800 is the Moon's nodal cycle
1733.333r is the Eclipse danger period in days x 10.
this is 40.8/13.or 81.6/26 or 163.2 / 52.
1.111111r / 1.0101010101r = 1.1 (base 11)
Edited 2 time(s). Last edit at 20-Jul-18 08:34 by DavidK.