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Hi David,
Found that several years ((4/3^2)^2 Even posted it in a post to Jim.
(4/3)^2 = 16/9:
(16/9)^2 = 256/81 Unfortunately I discount this as a misconception since the Ancient Egyptians did not use it in the manner you describe. Actually {8/9 diameter squared) was the Ancient Egyptian method for finding the 'area of a circle' not the circumference having nothing to do with pi as we employ it. Actually it is a derivative of the arc second circle.
You might give a little more consideration to the Heelstone, which is set at precisely 1/7 arc from true north, according to and quoting from: Temporal Epoch Calculations by James Q. Jacobs in which he states: “I noted that the latitude at Avebury equals the circumference of the earth divided by 7, with an error less than the diameter of Avebury. I later noted a simple geometric relation for Stonehenge's much-publicized Heel Stone alignment. The Heel Stone azimuth is precisely 51.4286° E. of N., also CIR/7. I had questioned the 'Heel Stone—winter solstice sunrise' alignment because the solstice azimuth has dramatically changed, and finding the Heel Stone's precise CIR/7 azimuth added to my doubts. ). I almost dismissed the summer solstice sunrise alignment rationale for the Heel Stone. CIR/7 not only fits the 'simplest explanatory theory' concept, it fits circularity. A 1/7-azimuth alignment in a circle makes more sense than apparent, time-varying solar motion. After all, one-seventh is a constant reference, not a moving target”
.
Regards,
Jacob
Found that several years ((4/3^2)^2 Even posted it in a post to Jim.
(4/3)^2 = 16/9:
(16/9)^2 = 256/81 Unfortunately I discount this as a misconception since the Ancient Egyptians did not use it in the manner you describe. Actually {8/9 diameter squared) was the Ancient Egyptian method for finding the 'area of a circle' not the circumference having nothing to do with pi as we employ it. Actually it is a derivative of the arc second circle.
You might give a little more consideration to the Heelstone, which is set at precisely 1/7 arc from true north, according to and quoting from: Temporal Epoch Calculations by James Q. Jacobs in which he states: “I noted that the latitude at Avebury equals the circumference of the earth divided by 7, with an error less than the diameter of Avebury. I later noted a simple geometric relation for Stonehenge's much-publicized Heel Stone alignment. The Heel Stone azimuth is precisely 51.4286° E. of N., also CIR/7. I had questioned the 'Heel Stone—winter solstice sunrise' alignment because the solstice azimuth has dramatically changed, and finding the Heel Stone's precise CIR/7 azimuth added to my doubts. ). I almost dismissed the summer solstice sunrise alignment rationale for the Heel Stone. CIR/7 not only fits the 'simplest explanatory theory' concept, it fits circularity. A 1/7-azimuth alignment in a circle makes more sense than apparent, time-varying solar motion. After all, one-seventh is a constant reference, not a moving target”
.
Regards,
Jacob
Subject | Views | Written By | Posted |
---|---|---|---|
Jacob's discovery | 1184 | DavidK | 24-Jan-18 11:57 |
Re: Jacob's discovery | 244 | DavidK | 25-Jan-18 06:48 |
Re: Jacob's discovery | 178 | DavidK | 25-Jan-18 14:07 |
Re: Jacob's discovery | 180 | DavidK | 25-Jan-18 14:36 |
Re: Jacob's discovery | 234 | Sirfiroth | 25-Jan-18 16:03 |
Re: Jacob's discovery | 149 | DavidK | 25-Jan-18 17:40 |
Re: Jacob's discovery | 210 | Sirfiroth | 25-Jan-18 18:48 |
Re: Jacob's discovery | 165 | DavidK | 26-Jan-18 22:21 |
Re: Jacob's discovery | 142 | Sirfiroth | 27-Jan-18 04:36 |
Re: Jacob's discovery | 150 | rodz111 | 27-Jan-18 06:55 |
Re: Jacob's discovery | 142 | drew | 27-Jan-18 00:54 |
Re: Jacob's discovery | 133 | Sirfiroth | 27-Jan-18 05:00 |
Re: Jacob's discovery | 120 | DavidK | 27-Jan-18 11:29 |
Re: Jacob's discovery and Egyptian PI? | 222 | DavidK | 27-Jan-18 11:52 |
Re: Jacob's discovery | 176 | DavidK | 09-Apr-18 20:34 |
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