root 2 initially is 99/70
Side of square inside the circle is 1 x root 2 = 99/70
perimeter of square is 4 x root 2
4 x 99/70 = 396/70
circumference of the circle ouside the square is 396/70 x 10/9 = 3960/630
and now i can add Jacob's calculation as 14/11
the csecond square perimeter becomes 55440 / 6930 = 8
there is a relationship between the perimeters of the two squares
A different version of root two is used
second version 140/99
396/70 x 140/99 = 4 x 2 = 8 per Jacob
This is the missing piece that proves the irrationality calculation is valid and can only be ancient.
Root 2 is bypassed.
99/70 x 140/99 = 2 never seen in a modern textbook this is the working of the ancient mind with no decimals to spoil things. Just fractional mathematics.
it works perfectly at SH
They knew exactly what they were doing when they laid out the circles.
1.414285714 = 99/70
1.414141414 = 140/99
1.414141414 x 39.60 = 56 postholes around SH.
Edited 2 time(s). Last edit at 25-Jan-18 14:41 by DavidK.
|Jacob's discovery||1163||DavidK||24-Jan-18 11:57|
|Re: Jacob's discovery||240||DavidK||25-Jan-18 06:48|
|Re: Jacob's discovery||175||DavidK||25-Jan-18 14:07|
|Re: Jacob's discovery||175||DavidK||25-Jan-18 14:36|
|Re: Jacob's discovery||225||Sirfiroth||25-Jan-18 16:03|
|Re: Jacob's discovery||146||DavidK||25-Jan-18 17:40|
|Re: Jacob's discovery||209||Sirfiroth||25-Jan-18 18:48|
|Re: Jacob's discovery||157||DavidK||26-Jan-18 22:21|
|Re: Jacob's discovery||134||Sirfiroth||27-Jan-18 04:36|
|Re: Jacob's discovery||147||rodz111||27-Jan-18 06:55|
|Re: Jacob's discovery||139||drew||27-Jan-18 00:54|
|Re: Jacob's discovery||124||Sirfiroth||27-Jan-18 05:00|
|Re: Jacob's discovery||113||DavidK||27-Jan-18 11:29|
|Re: Jacob's discovery and Egyptian PI?||218||DavidK||27-Jan-18 11:52|
|Re: Jacob's discovery||169||DavidK||09-Apr-18 20:34|