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This is what Hugh wrote

[hew_frank.tripod.com]

So Hugh finds the base as '

277.777 / 1.111r the UOIO = 250 so the GP base using Hugh's workings is 250 UOIO.

250 x 1.111r x 2.7207 = 755.75 imperial feet is the G1 base per the Encyclopedia Brittanica.

Hugh has found the real megalithic yard is always found in geometry but it is the design of the monuments that proves the designers themselves obviously knew this.

Edited 2 time(s). Last edit at 07-Dec-18 20:40 by DavidK.

[hew_frank.tripod.com]

*' After finding 2.72... emerging from various geometrical figures, it is inevitable that the pyramid must be examined.*

A 'Pi-Pyramid' is one whose vertical height to the perimeter of it's base, bears the same relationship as the Radius of a circle does to its Circumference. The slope angle of such a Pyramid is 51°51¢14×3²

Quite simply, the number of Ö3 units in the vertical height of such a pyramid, is the same number of 2.720699... units in one of the base sides. (i.e. If the height is 60Ö3 feet, the base is 60 MY).

A circle whose diameter is the vertical height, has a circumference of twice the number of units in the base side. (i.e. if the base is 60MY, then the circumference is 120MY).

Now in a 30/60 triangle, if the base side is 10,000 inches, the height will be 5773.5026... inches or 481.1252... feet. Which I do believe is as near as one can get to the actual height of the Gt. Pyramid. As such, the circumference of a circle on this measure (as a diameter) will be 555.555... MY, which means the base is 277.777... MY, or 755.749...feet, or 9068.99... inches. Flinders Petrie gives a mean measure of the four base sides as 9068.8 inches.

His height is 5776.0 +/- 7 inches, for his slope angle is steeper at 51°52¢

It also means that the base side is 1/360th of 100,000 MY, and thus the circumference must be 1/180th of100,000 MY., and that the height is 277.777...Ö3 feet.

Dividing the units in the base side of a Pi-type Pyramid by (2.720699... /2), produces the base side of an Equilateral triangle having the same vertical height . In the case of Gt.Pyramid, this Equilateral triangle will have sides of 555.555...feet.

So it looks as though our Imperial inch governs the dimensions of the Gt. Pyramid.'A 'Pi-Pyramid' is one whose vertical height to the perimeter of it's base, bears the same relationship as the Radius of a circle does to its Circumference. The slope angle of such a Pyramid is 51°51¢14×3²

Quite simply, the number of Ö3 units in the vertical height of such a pyramid, is the same number of 2.720699... units in one of the base sides. (i.e. If the height is 60Ö3 feet, the base is 60 MY).

A circle whose diameter is the vertical height, has a circumference of twice the number of units in the base side. (i.e. if the base is 60MY, then the circumference is 120MY).

Now in a 30/60 triangle, if the base side is 10,000 inches, the height will be 5773.5026... inches or 481.1252... feet. Which I do believe is as near as one can get to the actual height of the Gt. Pyramid. As such, the circumference of a circle on this measure (as a diameter) will be 555.555... MY, which means the base is 277.777... MY, or 755.749...feet, or 9068.99... inches. Flinders Petrie gives a mean measure of the four base sides as 9068.8 inches.

His height is 5776.0 +/- 7 inches, for his slope angle is steeper at 51°52¢

It also means that the base side is 1/360th of 100,000 MY, and thus the circumference must be 1/180th of100,000 MY., and that the height is 277.777...Ö3 feet.

Dividing the units in the base side of a Pi-type Pyramid by (2.720699... /2), produces the base side of an Equilateral triangle having the same vertical height . In the case of Gt.Pyramid, this Equilateral triangle will have sides of 555.555...feet.

So it looks as though our Imperial inch governs the dimensions of the Gt. Pyramid.'

So Hugh finds the base as '

**. MY, ' and this is 100000/360.***which means the base is 277.777..*277.777 / 1.111r the UOIO = 250 so the GP base using Hugh's workings is 250 UOIO.

250 x 1.111r x 2.7207 = 755.75 imperial feet is the G1 base per the Encyclopedia Brittanica.

Hugh has found the real megalithic yard is always found in geometry but it is the design of the monuments that proves the designers themselves obviously knew this.

Edited 2 time(s). Last edit at 07-Dec-18 20:40 by DavidK.

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