I should have said according to Petrie the South Side Socket base is 760 8/25 feet found here:
760.32 imperial feet is 9123.84 imperial inches. Please note this point is being made in imperial inches.
What does Petrie give for the south side socket base?
9123.90 imperial inches and as much as I would like it to be since it reconciles to 24883.20 miles per Michell you are not using Petrie's figure Jacob, you have inserted your own.
What you have done is not unreasonable and I applaud the fact that you have picked up on it but it simply is not Petrie's measurement unless you know how he rounded it from 3 sig figs.
Lets have a look at what difference it makes.
9123.9 x 4 x 3600 / 5280 = 24883.3636r imperial miles circumference against 24883.2 and what does the difference represent
24883.3636r - 24883.2 = 0.16363636r imperial miles and this is 864 imperial feet remembering there are 86400 seconds in one day and we are talking solar days here.
864/2 = 432 / 2 = 216 and there it is the 216 unit. also 432 / 0.12 = 3600 and this is in the canon of AM.
But there is even more to this than meets the Eye.
You know how I insist that the GP is designed against 366.666r x 1000 x 360 = 132000000 imperial feet 25000 imperial miles being 100000 units of 440 yards the length of the lesser cursus at Stonehenge.
Also that 440 needs to be restated because they used a foot of 0.99 of an imperial foot at SH so 440 is actually 444.444r feet, and this is 4 UOIO.
Well your alteration is messing up the calculation.
I am arguing that the builders intention here is to hit 24888.888r because 25000 - 24888.888r is 111.111r the UOIO.
The adjustment required to such complex measurements made by Petrie is less than a whisper. Each side has an interpretation and a significance but the whole produces the UOIO.
The average side length of 9125.925925925r does the exact trick.
111.111r x 5280 = 586666.6667 you will see this number many times in Rodz workings and x 6 it is 352000 and divided by 0.96 it is 366666.666r.It is about time.
and Jim said
Hi David and all
Petrie measured the socket sides and gave the mean as 9125.9 ins with a mean difference of 4.4.
The socket perimeter of the pyramid 9125.9 x 4 = 36503.6 inches and my first reaction was to think 36504 but look.
The Egyptian value for pi is being used as a tool. Height of Pyramid 280 Royal cubits Egyptian value for pi
3.160493827 x 280 = twice the socket base 884.9382716 x = 1769.876543 royal cubits and I have always used 20.625 inches so again 1769.876543 x 20.625 = 36503.7 inches.
The Egyptian value for pi has been used to take us to the socket perimeter and from there to an earth measure as the socket perimeter is 30 seconds of one degree. Hendrik may take note here as we are heading to something very close to a nauticle mile.
36503.7 / 12 = 3041.9753 feet x 2 = 6083.950617 feet one minute x 60 = 365037.037 one degree 69.1358027 miles this in one degree so x 360 = 24,888.88888 miles for a circumference. Now using The Egyptian method of find area and circumference divide the circumference by 4 ie 24,888.88888 / 4 = 6,222.22222.
6,222.2222 / 8 x 9 = 7,000 (squared is area of circle with a diameter of next) /8 x 9 = 7875 miles an earth diameter and one we are familiar with. 7875 miles = 12673.237km and if both are divided by 86400 the height of the pyramid is reached 7875 miles x 5280 = 41,580,000 feet / 86400 = 481.25 feet 146.685m 280 Royal cubits of 20.625 inches.
So looking at the ancient math all is not as it seems and it seems to me the ancients passed on knowledge in this way and only the initiated really knew.
20.625 / 0.99 = 20.83333333333r x 1760 = 36666.6666r the base 100 unit 20.625 being base 99.
Times up Jacob. 864/275 = Fibonacci Pi also.
Egyptian Pi had to be in the GP design and Jim has fixed it.
36503.7 gives 99555.54545 so 36666.666r gives 100000 hidden sacred numbers.
Edited 4 time(s). Last edit at 05-Dec-18 23:30 by DavidK.