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I believe the relationship between the imperial system and Thom's megalithic yard is by design.

5280 feet in one mile

2720 feet in 1000 megalithic yards

added together make 8000 and there are 8 furlongs in one mile

so dividing by 0.8 gives

6600 imperial as 100 chains

3400 Thom as 500 megalithic rods

So Thom and the imperial are parts of the greater whole.

Taking it down to 100 and dividing by the ecipse unit as 1.4666r gives

66 / 1.4666r = 45

34 / 1.4666r = 23.18181818

total 68.18181818 x 360 x 5280 = 129600000 a Babylonian unit found in Plimpton 322.

DTK copyright

note using inches the Roman foot reveals itself

63360

32640

96000

Edited 1 time(s). Last edit at 07-Jul-18 07:35 by DavidK.

5280 feet in one mile

2720 feet in 1000 megalithic yards

added together make 8000 and there are 8 furlongs in one mile

so dividing by 0.8 gives

6600 imperial as 100 chains

3400 Thom as 500 megalithic rods

So Thom and the imperial are parts of the greater whole.

Taking it down to 100 and dividing by the ecipse unit as 1.4666r gives

66 / 1.4666r = 45

34 / 1.4666r = 23.18181818

total 68.18181818 x 360 x 5280 = 129600000 a Babylonian unit found in Plimpton 322.

DTK copyright

note using inches the Roman foot reveals itself

63360

32640

96000

Edited 1 time(s). Last edit at 07-Jul-18 07:35 by DavidK.

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