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Jim wrote:

<To find your number exactly use the approx. for the cube root of 2 ie 1.26 x 3.125 = 3.9375.

And to do this by construction divide 39375 into 63 even spaces and measure to the 50th = 3.125.

Note; in Indus valley feet 31.25 is length of Kings chamber 412.5 inches 34.375 imperial feet>

Hi Jim,

Sorry for the delay responding to this interesting observation. That appx. ratio for doubling a cube formula comes in handy in a lot of ways looks like. I have been reviewing old discussions from nearly 6 yrs. ago, when I initially discovered the formula for the SOL, I am still using today, such as this post mentions:

<[grahamhancock.com];

Other than the observation that Time sure has flown since this initial discovery, what else have I learned since then? LOL! That this formula for the SOL is directly tied into the dimensions of the Earth Geoid model I have been formulating for years previous, and not much else actually. However, since both Light and Gravity are both tied into this speed, this formula was useful for other aspects of my investigations as well. The most unusual being a description that John Michell was working on regarding the Chapel of Mary, in Glastonbury long ago. Which I mentioned here:

<[grahamhancock.com];

And this followup post that resolved one of JM's estimates of the Roman pace of 2.5 Roman Ft. mentioned here:

<[grahamhancock.com];

So there's little doubt that the Polar Meridian Circ. value I have been using was known even into the Middle Ages, but mostly as a weight ratio between the Av/Lb. of 7000gr, and the heavier Hanseatic Lb. of 7200gr,, or 35/36, that also exists between the Imp.Ft. and the Roman Ft. inversely proportional.

This earlier study of the Gravitational Force acting on the Earth's Oblate shape, was calculated at the Perigee point of the Earth/Moon system's orbit around the Sun. I later did a recalculation of that formula using the average Canonical Mean between this Perigee and Apogee ratio of 384/400, or 24/25 of 392 or half of the total 400 + 384 = 784 total diameter units of the Earth/Moon system. That calculation became the basis for my followup discussion last year found here:

<[grahamhancock.com];

The only problem with that calculation is the fact that I got the Earth/Sun distance incorrectly stated as 1177/1176, when it should have been 11761/11760. Oh well, can't get it right all the time. But more to the point of this secondary Gravitational study discussion, what is the actual extraneous force other than the Luni/Sol factor, which I can restate correctly as (31/30 x 11761/11760)^2 = 1.06795938, acting on the Earth's Oblate shape? This is actually a lower factor than the initial calculation due to it being a median value of the combined Luni/Sol gravitational force acting on the Earth's orbit around the Sun. And does it have something to do with the differential value of the Chapel of Mary floor plan dimensions?

I guess the only way to find out is to do like F.Bligh Bond did and contact those deceased Glastonbury monks, cause I seriously doubt I will get any good answers on this Message board. I'd be better off using a Ouija board, LOL!

Best regards,

Stephen

<To find your number exactly use the approx. for the cube root of 2 ie 1.26 x 3.125 = 3.9375.

And to do this by construction divide 39375 into 63 even spaces and measure to the 50th = 3.125.

Note; in Indus valley feet 31.25 is length of Kings chamber 412.5 inches 34.375 imperial feet>

Hi Jim,

Sorry for the delay responding to this interesting observation. That appx. ratio for doubling a cube formula comes in handy in a lot of ways looks like. I have been reviewing old discussions from nearly 6 yrs. ago, when I initially discovered the formula for the SOL, I am still using today, such as this post mentions:

<[grahamhancock.com];

Other than the observation that Time sure has flown since this initial discovery, what else have I learned since then? LOL! That this formula for the SOL is directly tied into the dimensions of the Earth Geoid model I have been formulating for years previous, and not much else actually. However, since both Light and Gravity are both tied into this speed, this formula was useful for other aspects of my investigations as well. The most unusual being a description that John Michell was working on regarding the Chapel of Mary, in Glastonbury long ago. Which I mentioned here:

<[grahamhancock.com];

And this followup post that resolved one of JM's estimates of the Roman pace of 2.5 Roman Ft. mentioned here:

<[grahamhancock.com];

So there's little doubt that the Polar Meridian Circ. value I have been using was known even into the Middle Ages, but mostly as a weight ratio between the Av/Lb. of 7000gr, and the heavier Hanseatic Lb. of 7200gr,, or 35/36, that also exists between the Imp.Ft. and the Roman Ft. inversely proportional.

This earlier study of the Gravitational Force acting on the Earth's Oblate shape, was calculated at the Perigee point of the Earth/Moon system's orbit around the Sun. I later did a recalculation of that formula using the average Canonical Mean between this Perigee and Apogee ratio of 384/400, or 24/25 of 392 or half of the total 400 + 384 = 784 total diameter units of the Earth/Moon system. That calculation became the basis for my followup discussion last year found here:

<[grahamhancock.com];

The only problem with that calculation is the fact that I got the Earth/Sun distance incorrectly stated as 1177/1176, when it should have been 11761/11760. Oh well, can't get it right all the time. But more to the point of this secondary Gravitational study discussion, what is the actual extraneous force other than the Luni/Sol factor, which I can restate correctly as (31/30 x 11761/11760)^2 = 1.06795938, acting on the Earth's Oblate shape? This is actually a lower factor than the initial calculation due to it being a median value of the combined Luni/Sol gravitational force acting on the Earth's orbit around the Sun. And does it have something to do with the differential value of the Chapel of Mary floor plan dimensions?

I guess the only way to find out is to do like F.Bligh Bond did and contact those deceased Glastonbury monks, cause I seriously doubt I will get any good answers on this Message board. I'd be better off using a Ouija board, LOL!

Best regards,

Stephen

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