Mysteries :
The Official GrahamHancock.com forums

For serious discussion of the controversies, approaches and enigmas surrounding the origins and development of the human species and of human civilization. (NB: for more ‘out there’ posts we point you in the direction of the ‘Paranormal & Supernatural’ Message Board).

'Personally, finding streams of numbers that fit together and then claiming the ancients must have done the same thing feels a little uncomfortable to me, but like I said, who really knows? '

Obviously not getting the message across.

Only one number is involved 14.666r and this has been named the ECLIPSE UNIT. It is 14.666r one number only or as the ancients may have known it 440 / 30. ( 440 cubits is in the base of the GP regardless of the length of the cubit, which seems to have been of variable length based on available evidence).

Thom said that base 10 was probably considered universally sacred and that they seemed to be using Pi as 22/7 on page 47 of his first book. Since we have 10 digits on our hands this seems a very plausible observation.

14.666r divided by 22/7 is 4.666r and the difference is 10 so this evidence seems to support Thom's assertion since base 10 is included in the number 14.666 when the diameter is taken from it.

This number 14.666r comes from one place only. The Saros cycle. 6585.333 days.

So what is the evidence for 14.666r?

It is on the NASA website overseen by Fred Espanek some one who knows more about eclipses than anyone possibly.

The eclipse period is 18 years 11 days and 8 hours.

8 hours is 0.3333r of a day and this is where the 1/3 comes from in 6585.333r.

6600 or 100 imperial chains is 6600 in numbers less 6585.333r = 14.666r.

6585.333r is a number that has been derived from the Antikithera mechanism.

So this number has been evidenced to an ancient source.

There is a big problem with 18 years because now the argument will be

Your numbers are wrong because 18 x 365.242 plus 11 and 1/3 days is not 6585.333r it is 6585.689333 so you numbers are wrong. Or even worse using 365.25 giving 6585.833333.

But the solution to this tricky problem is not insurmountable and to get to 14.666r, the single number being talked about here, the solar day has to be restated from 365.25 to an eclise year which is slightly different. This does not affect the length of the day.

Before looking at this lets gat back to Thom and where does his unit come from? It is embedded very easily in the last part of the eclipse if we multiply the number by 3 so 440/30 becomes 440/10. ( the length of the lesser cursus at SH is 440 yards and of the side of the GP 440 cubits. I do not deny that this could be coincidence).

11 days eight hours is 11.333r days x 3 = 34 a base 17 number and one half of Thom's megalithic rod. It really is that easy to find Thom in the eclipse.

If we multiply the eclipse Saros by 3 we get 6585.333r x 3 = 19756. The base side of the GP in 10 cubit units is 44. 19756 / 44 = 449 an exact number. Thom insisted that the ancients had to have their circumferences in whole numbers.

We are still only looking at one number here 14.666r i just want to make that very clear.

No 'finding streams of numbers that fit together' So back to the problem of the length of the solar year.

For my calculation to work 18 years has to represent 6585.333 - 11.333 = 6574 days, a whole number.

6574 / 18 = 365.222r exactly.

Now this is the rub.

365.25 - 365.222r = 0.002777r.

It would be very uncomfortable if the figure seemingly plucked out of nowhere could not be reconciled to an ancient unit of measure.

But what is this number?

it is 1/360 = 0.00277r. It fits like a glove.

Of all the coincidences in the Galaxy the eclipse takes the biscuit if you don't mind the pun. Not only is the Moon the exact size of the distant Sun when viewed from the Earth the ancients appear to have discovered the biggest mathematical coincidence of all time as well.

Why do we suspect they discovered it?

One reason is that in the imperial system one mile is 5280 units / 360 = 14.666r.

Another is the the Babylonian barleycorn very appropriately named the 'SHE' is 0.002777r units in length.

Another is that there are 5280 'SHE's' in 14.666r

Another is that the English barleycorn is 1320 'SHE's'

Another is that 10 English barleycorn are 3.666r or 11/3 units

Another is that 3.666r / 7 x 6 = 22/7 Thom's Pi discovery at Avebury.

Another is that the unit 22/42 or 11/21 is included in a Bauval lecture on the GP as 0.523809524 or P1 / by 6.

I could go on but you get the drift.

Oh and 21/11 is 1.5 x the Sekhed.

One number only being discussed here, and it is 14.666r the Eclipse unit.

height of GP is 146.66r base side is 146.666r - not my numbers.

What this all mean is that solar days can be restated into whole numbers using a broken down analysis of the 'SHE'

this is 0.002777r / 0.00111r = 2.5 The unit Thom discovered in his analysis of Avebury.

365.25 / 0.00111r = 328725

365.222r / 0.00111r = 328700

364 / 0.00111r = 327600

366 / 0.00111r = 329400

366.5 / 0.00111r = 329850

366.666r / 0.00111r = 330000

366.666r is 10000 english barleycorns or 100 squared barleycorns.

366.666r / 0.002777r = 132000

1466.666r / .002777r = 528000.

This is Michell's CANON of ANCIENT MEASURE.

Edited 8 time(s). Last edit at 01-Feb-18 10:42 by DavidK.

Obviously not getting the message across.

Only one number is involved 14.666r and this has been named the ECLIPSE UNIT. It is 14.666r one number only or as the ancients may have known it 440 / 30. ( 440 cubits is in the base of the GP regardless of the length of the cubit, which seems to have been of variable length based on available evidence).

Thom said that base 10 was probably considered universally sacred and that they seemed to be using Pi as 22/7 on page 47 of his first book. Since we have 10 digits on our hands this seems a very plausible observation.

14.666r divided by 22/7 is 4.666r and the difference is 10 so this evidence seems to support Thom's assertion since base 10 is included in the number 14.666 when the diameter is taken from it.

This number 14.666r comes from one place only. The Saros cycle. 6585.333 days.

So what is the evidence for 14.666r?

It is on the NASA website overseen by Fred Espanek some one who knows more about eclipses than anyone possibly.

The eclipse period is 18 years 11 days and 8 hours.

8 hours is 0.3333r of a day and this is where the 1/3 comes from in 6585.333r.

6600 or 100 imperial chains is 6600 in numbers less 6585.333r = 14.666r.

6585.333r is a number that has been derived from the Antikithera mechanism.

So this number has been evidenced to an ancient source.

There is a big problem with 18 years because now the argument will be

Your numbers are wrong because 18 x 365.242 plus 11 and 1/3 days is not 6585.333r it is 6585.689333 so you numbers are wrong. Or even worse using 365.25 giving 6585.833333.

But the solution to this tricky problem is not insurmountable and to get to 14.666r, the single number being talked about here, the solar day has to be restated from 365.25 to an eclise year which is slightly different. This does not affect the length of the day.

Before looking at this lets gat back to Thom and where does his unit come from? It is embedded very easily in the last part of the eclipse if we multiply the number by 3 so 440/30 becomes 440/10. ( the length of the lesser cursus at SH is 440 yards and of the side of the GP 440 cubits. I do not deny that this could be coincidence).

11 days eight hours is 11.333r days x 3 = 34 a base 17 number and one half of Thom's megalithic rod. It really is that easy to find Thom in the eclipse.

If we multiply the eclipse Saros by 3 we get 6585.333r x 3 = 19756. The base side of the GP in 10 cubit units is 44. 19756 / 44 = 449 an exact number. Thom insisted that the ancients had to have their circumferences in whole numbers.

We are still only looking at one number here 14.666r i just want to make that very clear.

No 'finding streams of numbers that fit together' So back to the problem of the length of the solar year.

For my calculation to work 18 years has to represent 6585.333 - 11.333 = 6574 days, a whole number.

6574 / 18 = 365.222r exactly.

Now this is the rub.

365.25 - 365.222r = 0.002777r.

It would be very uncomfortable if the figure seemingly plucked out of nowhere could not be reconciled to an ancient unit of measure.

But what is this number?

it is 1/360 = 0.00277r. It fits like a glove.

Of all the coincidences in the Galaxy the eclipse takes the biscuit if you don't mind the pun. Not only is the Moon the exact size of the distant Sun when viewed from the Earth the ancients appear to have discovered the biggest mathematical coincidence of all time as well.

Why do we suspect they discovered it?

One reason is that in the imperial system one mile is 5280 units / 360 = 14.666r.

Another is the the Babylonian barleycorn very appropriately named the 'SHE' is 0.002777r units in length.

Another is that there are 5280 'SHE's' in 14.666r

Another is that the English barleycorn is 1320 'SHE's'

Another is that 10 English barleycorn are 3.666r or 11/3 units

Another is that 3.666r / 7 x 6 = 22/7 Thom's Pi discovery at Avebury.

Another is that the unit 22/42 or 11/21 is included in a Bauval lecture on the GP as 0.523809524 or P1 / by 6.

I could go on but you get the drift.

Oh and 21/11 is 1.5 x the Sekhed.

One number only being discussed here, and it is 14.666r the Eclipse unit.

height of GP is 146.66r base side is 146.666r - not my numbers.

What this all mean is that solar days can be restated into whole numbers using a broken down analysis of the 'SHE'

this is 0.002777r / 0.00111r = 2.5 The unit Thom discovered in his analysis of Avebury.

365.25 / 0.00111r = 328725

365.222r / 0.00111r = 328700

364 / 0.00111r = 327600

366 / 0.00111r = 329400

366.5 / 0.00111r = 329850

366.666r / 0.00111r = 330000

366.666r is 10000 english barleycorns or 100 squared barleycorns.

366.666r / 0.002777r = 132000

1466.666r / .002777r = 528000.

This is Michell's CANON of ANCIENT MEASURE.

Edited 8 time(s). Last edit at 01-Feb-18 10:42 by DavidK.

Sorry, only registered users may post in this forum.