Quote '583.92(days)=Venus synodic period (NASA)'
583.92 imperial feet / 6 = 97.32 imperial feet 1167.84 inches Petrie Stonehenge diameter = 1167.9 +-7 inches
the eclipse system reveals itself,
We only need two points on the line and we have them
97.32 x 30 = 2919.6
97.4 x 30 = 2922
so 100 = 3000
mutiply by 3.75 to get solar days and by 30 to get the 8 year cycle. ( 30 sarsen stones.)
Where does the eclipse system top out
97.777s x 3.75 = 366.666r and 97.777r x 30 = 2933.333r this is 100 eclipse months of 29.333r days.
Divide by 2 97.777r / 2 = 48.888r divide by 3.33333333 = 14.666r
97.777r /6.666r = 14.666r
the base unit in the system is 100 - 97.777r = 2.222r / 2 = 1.111r and this is 10/9
the solar year is 365.25
The eclipse year is 365.222r
Difference is 0.0027777777777777777r
x 100 = 0.2777r divide by the base unit 1.111r = 2.5 Thom's discovery at Avebury.
Using the canon of ancient measure.
365.222r x 360 x 1000 = 131480000
131480000 / 5280 = 24901.51515
132000000-131480000 = 520000 x 7 = 3640000 = 10000 solar years or 100 x 100 using 1/7 foot for 1 day.
So the eclipse system is the canon of Ancient measure where 1000 miles 5280000 feet represent 52800/( 360 x 1000 ) = 14.666r solar days.
14.666r divided by the system base unit is 14.666r /1.111r = 13.20.
0.0027777r is the babylonian unit 1/360 the sexigesimal system.
Hugh Franklin finds this unit in his GP workings.
As a point of interest for Rodz.
The picture of the Lech stones you posted has two little mounds in the distant hills.
This could be my countryside in Derbyshire, England, a most beautiful landscape. All the highest hills have ancient mounds on them just like your picture. I think of them as 'mini Silbury hills'. Many of them are 'bowl' barrows. Horizonal observation points all linked using the imperial system of measurement.
Thom said of our ancestors.
' As far as brainpower is concerned, they were my superiors'
He was an Oxford professor!!
And now we can find the Thom unit.
His analysis of Avebury is the single most important piece of historical surveying ever undertaken and his results are astonishing claiming he had the whole site laid out exactly as the ancients did it to an accuracy of over 1 in 1000 so no room for error.
The THOM UNIT can be produced by an analysis of his findings.
He had the perimeter of the ring as 6.8 x 521 feet = 3542.8 feet very close to 10 lunar years.
using 521 units x 7 = 3647 days and this can be assessed using the eclipse system.
this adjustment uses the Roman foot as 34/35 = 0.971428571
3647 x 8 = 29176 and the base is 29220
29220 -29176 = 44 days / 3 = 14.666r days. THE ECLIPSE and THOM UNIT.
Thom's analysis of Avebury identifies the eclipse unit using the Roman foot in the analysis.
From the very outset i have been trying to bring attention to Thom's work.
He was absolutely correct the Avebury ring is over 2/3 of a mile in perimeter and has a beautiful English village inside of it with a National Trust manor house, pub and glorious church.
None of this is in my book because i have only worked it out today!!
It is a completely numerically balanced analysis of Thom's findings at Avebury.
Edited 8 time(s). Last edit at 30-Jan-18 12:02 by DavidK.