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Suppose...

Earth rotates at an approx. rate of 1° of arc for every 72 orbits of the Sun. Comprising of 26 297,424 DAYS x 360° = 9 467 072,64 days in a PRECESSION CYCLE, during which true Polar Wander completes a circle of 72° dia. -i.e. revolving 360° in 25 920 YEARS

9 467 072,64 DAYS, we recall, (25 920 X 365.242) constitutes a precession cycle

9 467 072,64 divided by 360° = 26 297,424 DAYS for Earth to rotate 1° of arc rearward.

Therefore, 21600 minutes divided by 26 297,424 = 0,82137323 MINUTES of arc PER DAY to effect a shift of 1° in 72 years ?

In a mix of angular distance and time... continual counter rotation of two intersecting cycles: East in a 24hr day -VS- WestSouthWest revolution per precession rate. The latter subjects the former to a shortfall - DAY CHANGE FACTOR - daily East requiring additional time, to close the arc of its respective 360°

365.242 x 1440 = 525 949 MINUTES in a SolarYear x72

= approx. 37 868 328 MINUTES to 1° DEGREE of ARC

IN SUMMARY -employing a refined rotation rate:

completing ONE DEGREE of ARC in 71,5 years -i.e. 26115 days. Therefore, a 360° revolution takes 25740 YEARS, which is comprised of 9 401 535 DAYS

26115 x 360° = 9 401 535 MINUTES -i.e. 1min. per 1° of arc, which constitutes 71,5 years, accumulates to the equivalent number of days comprising a precession cycle.

The number of DAYS thus reconcile in equal number with MINUTES, which demonstrates the CORRELATION between the cycles - both relate to a mutual constant, being

please review, if you will

Edited 1 time(s). Last edit at 18-Mar-17 15:32 by hendrik dirker.

Earth rotates at an approx. rate of 1° of arc for every 72 orbits of the Sun. Comprising of 26 297,424 DAYS x 360° = 9 467 072,64 days in a PRECESSION CYCLE, during which true Polar Wander completes a circle of 72° dia. -i.e. revolving 360° in 25 920 YEARS

QuoteKEY

1x orbit of the Sun = SolarYear = 365.242 days / 525949 min.

1min. of arc = 1 nautical mile / 1.852 km

1 nautical mile = 1/60 degree

1° longitude = 60 nautical miles

Earth's circumference

21 639 nautical miles / 40 075km

360° comprises 21600 min. of arc 1° of arc = 60min. divided by 1min. of arc = 60sec.

time rounded: 60minutes in 1hour, comprising of 1440 min. in 24hrs = one 360° revolution

the equinox advances around the ecliptic at a rate of +-50.291 arc seconds PER YEAR..

9 467 072,64 DAYS, we recall, (25 920 X 365.242) constitutes a precession cycle

9 467 072,64 divided by 360° = 26 297,424 DAYS for Earth to rotate 1° of arc rearward.

Therefore, 21600 minutes divided by 26 297,424 = 0,82137323 MINUTES of arc PER DAY to effect a shift of 1° in 72 years ?

In a mix of angular distance and time... continual counter rotation of two intersecting cycles: East in a 24hr day -VS- WestSouthWest revolution per precession rate. The latter subjects the former to a shortfall - DAY CHANGE FACTOR - daily East requiring additional time, to close the arc of its respective 360°

365.242 x 1440 = 525 949 MINUTES in a SolarYear x72

= approx. 37 868 328 MINUTES to 1° DEGREE of ARC

IN SUMMARY -employing a refined rotation rate:

completing ONE DEGREE of ARC in 71,5 years -i.e. 26115 days. Therefore, a 360° revolution takes 25740 YEARS, which is comprised of 9 401 535 DAYS

26115 x 360° = 9 401 535 MINUTES -i.e. 1min. per 1° of arc, which constitutes 71,5 years, accumulates to the equivalent number of days comprising a precession cycle.

The number of DAYS thus reconcile in equal number with MINUTES, which demonstrates the CORRELATION between the cycles - both relate to a mutual constant, being

**360**- one revolution each. As such the impact induced DAY CHANGE component will FACTOR proportionately (for ease of calculation at my level of ability, I infer I min. / day - it could however entail a fraction).please review, if you will

Edited 1 time(s). Last edit at 18-Mar-17 15:32 by hendrik dirker.

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